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Alika [10]
3 years ago
10

The function f(x) = x2 + 6x + 3 is transformed such that g(x) = f(x − 2). Find the vertex of g(x).

Mathematics
1 answer:
garri49 [273]3 years ago
6 0

Answer:

(-1,-6)

Step-by-step explanation:

f(x)=x^2+6x+3

g(x)=f(x-2)

g(x)=(x-2)^2+6(x-2)+3  (Replaced x in f with (x-2))

g(x)=x^2-4x+4+6x-12+3 (Used (x+b)^2=x^2+2bx+b^2 and distributive property)

g(x)=x^2-4x+6x+4-12+3 (Gathered like terms)

g(x)=x^2+2x-5  (Simplified)

The vertex of a parabola occurs at (\frac{-b}{2a},g(\frac{-b}{2a}).

Let's find \frac{-b}{2a} first.

\frac{-2}{2(1)}=-1

Now we can obtain g(\frac{-b}{2a}) which is g(-1) in this case:

g(x)=x^2+2x-5

g(-1)=(-1)^2+2(-1)-5

g(-1)=1-2-5

g(-1)=-1-5

g(-1)=-6.

The vertex is (-1,-6).

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