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MArishka [77]
3 years ago
5

Can someone please help me with this! I'll do my best to give a lot of points for it!

Mathematics
1 answer:
Triss [41]3 years ago
8 0
1. By combining like terms
2. Same variable = same term, so you can combine them
3. Because 2y - y = 1y , and 1y is the same as y because a y is one y (obviously)
4. 1/2 + 1/2 = 1. A half an x and a half an x makes one whole x, therefore, x
5. No. You solve them like you would a normal equation with like terms. So it would be 3z^2

Hopefully these are right, I’m a bit rusty!
6. 4x
7. 3y
8. y - 4.5
9. 3.5x + 2
10. 4y + 2
11. 7x
12. 2.2w - 0.5
13. 23b + 6.6
14. 3.75x + 1.5
15. 0.8x + 2.1
Good luck, I hope this helped
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Help me plsss ill give ten pointsssss
Bond [772]

Answer:

A

Step-by-step explanation:

AE=EC

5x-10=2x+5

5x-2x=5+10

3x=15

x=5

6 0
3 years ago
Read 2 more answers
A theater is selling tickets for a performance. Mr. Smith purchased 8 senior tickets and 5 child tickets for $136 for his friend
ICE Princess25 [194]

Answer:

The price of a senior ticket is $12.

Step-by-step explanation:

Given:

Mr. Smith purchased 8 senior tickets and 5 child tickets for $136. Mr. Jackson purchased 4 senior tickets and 6 child tickets for $96.

Now, to get what is the price of a senior ticket.

Let the senior ticket be x and the child ticket be y:

So, according to question

8x+5y=136.........(1)

4x+6y=96...........(2)

Now, we have system of equations:

Multiplying the equation (2) by -2 we get:

-8x-12y=-192.......(3)

Now, adding the equation (3) and (1) the variables and the numbers:

-8x-12y+8x+5y=-192+136

-7y=-56

Dividing both sides by -7 we get:

y=8

Putting the value of y in equation (2) we get:

4x+6(8)=96

4x+48=96

On solving the equation we get:

x=12.

Therefore, the price of a senior ticket is $12.

4 0
3 years ago
Which of the following equations could be th equation to represent the given graph? Make sure you explain your answer thoroughly
Alex17521 [72]

Answer:

Option (C) is correct.

Step-by-step explanation:

The given options of the possible equation for the graph are as follows:

(A) y=2\left(\frac{3}{2}\right)^x \\\\(B) y=-2\left(\frac{3}{2}\right)^{-x} \\\\(C) y=2\left(\frac{2}{3}\right)^x \\\\(D) y=-2\left(\frac{2}{3}\right)^{-x} \\\\

The given graph is decreasing and at x=0, y=2.

So, first checking the value of the given options for x=0

(A) y=2\left(\frac{3}{2}\right)^0=2\times 1= 2 \\\\(B) y=--2\left(\frac{3}{2}\right)^{-0}= -2\times 1= -2 \; (not\; possible) \\\\(C) y=2\left(\frac{2}{3}\right)^0= 2\times 1= 2 \\\\(D) y=2\left(\frac{2}{3}\right)^{-0} = -2\times 1= -2 \; (not\; possible)

As, for x=0, y=2, so options (C) and (D) are not possible, so rejected.

Now, checking the nature (increasing or decreasing) of the given equation by differentiating it.

For option (A),

\frac{dy}{dx}=2\left(\frac{3}{2}\right)^{x}\times \ln\left(\frac{3}{2}\right)

As \ln \left(\frac{3}{2}\right)=\ln(1.5)>0 \;and\; \left(\frac{3}{2}\right)^{x} >0

So, \frac{dy}{dx}>0

Therefore, the function in option (A) is increasing function.

Similarly, for option (C),

\frac{dy}{dx}=2\left(\frac{2}{3}\right)^{x}\times \ln\left(\frac{2}{3}\right)

As \ln \left(\frac{2}{3}\right)=\ln(0.67)0

So, \frac{dy}{dx}

Therefore, the function in option (C) is decreasing function.

As the given graph is decreasing, so, (C)  representsy=2\left(\frac{2}{3}\right)^x the given graph.

Hence, option (C) is correct.

6 0
3 years ago
I need the answer for this question
aleksley [76]
Yup it’s b for sure
4 0
3 years ago
Please help me. I have no idea to this question.<br> a) 3ax+3ay-bx-by<br> b) 10ay²-5by²+2a²y-aby
vladimir2022 [97]

Answer:

a)3a(x+y)-b(x+y)

=(3a-b)(x+y)

b)5y(2ay-by)+a(2ay-by)

=(5y+a)(2ay-by)

7 0
3 years ago
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