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GalinKa [24]
3 years ago
8

Write the equation y = 0.445x + 14.7 as function P.

Mathematics
1 answer:
sergey [27]3 years ago
5 0

Given:

The equation is

y = 0.445x + 14.7

To find:

The given equation as function P.

Solution:

We have, the given equation y = 0.445x + 14.7, to write it as a function P, we need to substitute y=P(x) in the given equation.

On substituting y=P(x) in equation y = 0.445x + 14.7, we get

P(x)= 0.445x + 14.7

Therefore, the required function is P(x)= 0.445x + 14.7.

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Answer:

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}

Step-by-step explanation:

Given

(\frac{6}{10})^3 * (\frac{5}{9})^2

Required

Solve:

(\frac{6}{10})^3 * (\frac{5}{9})^2

Simplify 6/10

(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{9})^2

Express 9 as 3^2

(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{3^2})^2

Apply law of indices

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{(3^2)^2}

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Express as a sing;e fraction

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3*5^2}{5^3*3^4}

Apply law of indices:

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^{3-2}*3^{4-3}}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^1*3^1}

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(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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