Answer:
-8 = d
Step-by-step explanation:
-10 = -2+d
Add 2 to each side
-10 +2 = -2+2 +d
-8 = d
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Answer:
θ = 2 π n_1 + π/2 for n_1 element Z or θ = 2 π n_2 for n_2 element Z
Step-by-step explanation:
Solve for θ:
cos(θ) + sin(θ) = 1
cos(θ) + sin(θ) = sqrt(2) (cos(θ)/sqrt(2) + sin(θ)/sqrt(2)) = sqrt(2) (sin(π/4) cos(θ) + cos(π/4) sin(θ)) = sqrt(2) sin(θ + π/4):
sqrt(2) sin(θ + π/4) = 1
Divide both sides by sqrt(2):
sin(θ + π/4) = 1/sqrt(2)
Take the inverse sine of both sides:
θ + π/4 = 2 π n_1 + (3 π)/4 for n_1 element Z
or θ + π/4 = 2 π n_2 + π/4 for n_2 element Z
Subtract π/4 from both sides:
θ = 2 π n_1 + π/2 for n_1 element Z
or θ + π/4 = 2 π n_2 + π/4 for n_2 element Z
Subtract π/4 from both sides:
Answer: θ = 2 π n_1 + π/2 for n_1 element Z
or θ = 2 π n_2 for n_2 element Z
Answer:
They are right, the time calculated using the exponential decay equation is 1948.6 years.
Step-by-step explanation:
The time can be calculated using the exponential decay equation:
(1)
<u>Where</u>:
N(t): is the quantity of C-14 at time t
N₀: is the initial quantity of C-14
λ: is the decay constant
The decay constant is:
(2)
By entering equation (2) into (1) and solving for t, we have:

Therefore, the time of the scrolls estimated by the archeologists is right, since the time calculated using the exponential decay equation is 1948.6 years.
I hope it helps you!
Th matrix is missing. The matrix is :

Solution :
The column of the matrix are
,
, 
Now each of them are vectors in
. But
has dimensions of 2. But there are 3 column vectors, hence they are linearly dependent.
Therefore, the column of the given matrix does not form the
as the set contains
than there are entries in each vector.
Therefore, option (D) is correct.