1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vladimir1956 [14]
3 years ago
10

Solve each equation for the given variable: 1) 6a+5a=-11

Mathematics
2 answers:
ivanzaharov [21]3 years ago
4 0
6a+5a=-11 \\
(6+5)a=-11 \\
11a=-11 \\
a=\frac{-11}{11} \\
a=-1
LUCKY_DIMON [66]3 years ago
3 0
6a + 5a=-11. So, 11a=-11 => a =  \frac{-11}{11} , and   a =-1.
You might be interested in
Using the digits 0-9 at most one time each fill in the boxes so that the fraction equals the decimal
Zinaida [17]

Step-by-step explanation:

Z 00m

336"083"2553

(wZE2XQ) are

8 0
3 years ago
The ages of the people who came to a birthday party are shown below. Which statements must be true according to the histogram? C
spayn [35]
From the histogram it can be seen that
1.) the data is not qualitative. (<span>Qualitative data is typically descriptive <span>data and is not measured by a number but age is measured by a number).
2.) </span></span><span>The data is not skewed right. (</span><span>For a right skewed distribution, the tail of the distribution on the right hand (positive) side is longer than on the left hand side).
3.) </span><span>There were 31 people at the party. (The total number of people at the party from the histogram is given by the sum of the heights of the bars of the histogram = 5 + 13 + 8 + 3 + 2 = 31).
4.) </span><span>There were children at the party. (From the histogram, there were 5 poeple aged 20 and below, which we can describe as children).
5.) </span><span>The most common age of the attendees was not 13 years old. (The mode (i.e. most occuring frequency) of a distribution is represented by the height of the tallest bar of the histogram. From the histogram, the tallest bar represents the ages between 21 to 40)
6.) </span><span>The majority of the people at the party were less than 61 years old. (From the histogram, there were 5 + 13 + 8 = 26 people below the age of 61 in the party and 3 + 2 = 5 people above the age of 60 in the party).

Therefore, the </span><span>statements that must be true according to the histogram are
</span><span>There were 31 people at the party.
</span><span>There were children at the party.
and
</span><span>The majority of the people at the party were less than 61 years old.</span>
5 0
3 years ago
Read 2 more answers
Press on the picture to see the full picture. I’m really stuck
stepladder [879]
D should be the correct answer :)
4 0
3 years ago
Read 2 more answers
1,1,4,3,9,6,16,10,25,15,
Butoxors [25]

what are we suppose to do in this?

6 0
3 years ago
My teacher never explained how to do this so im kinda lost so can i get help and get the answers on these please(ASAP)
ivolga24 [154]

Answer: This shat def a virus

Step-by-step explanation:

7 0
3 years ago
Other questions:
  • Without drawing the graphs, find the points of intersection of the lines:
    6·1 answer
  • Enrique Gonzales owns a small publishing house specializing in Latin American poetry. His fixed cost to produce a typical poetry
    11·1 answer
  • I need this for a quiz, pls help lol
    11·1 answer
  • Answer these 2 questions please
    13·2 answers
  • Which expression is equivalent to the area of metal sheet required to make this square-shaped traffic sign? I WILL GIVE BRAINLYI
    13·1 answer
  • Which expressions are equivalent to 71-x-3)? Select two options.
    14·1 answer
  • A car traveling at 10 m/s starts to slow down. It comes to a complete stop
    12·1 answer
  • Calculate the mean of the data set {62, 75, 85, 63,69, 72, 76, 84, 87,88} round to the nearest tenth ?
    10·1 answer
  • 5 Miles 17 Deer 5 Mlies Predict the number of deer in a 25 square mile section of the mountains based on the sampling from the f
    14·1 answer
  • PLEASE HELP ME PRESS THE PHOTO ABOVE
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!