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3 years ago

Solve each equation for the given variable: 1) 6a+5a=-11

Mathematics

2 answers:

ivanzaharov [21]3 years ago

4 0

$6a+5a=-11 \\
(6+5)a=-11 \\
11a=-11 \\
a=\frac{-11}{11} \\
a=-1$

LUCKY_DIMON [66]3 years ago

3 0

$6a + 5a=-11. So, 11a=-11 => a = \frac{-11}{11} , and a =-1.$

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What should be done so that the expression will have a value of 10? 12 - 2 + 2 2 ÷ 8

Liula [17]

Answer: 10
use (PEMDAS)
P parentheses ()
E exponents
M multiplication • , () , x
D division
A addition +
S subtraction -
Explanation:
There are no parentheses.
There are exponents.
The multiplication is the exponents.
There is division.
There is addition and subtraction.
-how to solve-
First, do 2 to the second power and get 4.
Next, do 12-2+4 divided by 8.
Next do multiplication: there’s no more.
Next do division: you can’t do 4 divided by 8 so instead, do 12-2 = 10 plus 8.
Hope this helps!

3 0

3 years ago

Factor completely:

Sergio [31]

Answer:

a.-(p-1)(p-6)

b.(a+2)(a+2-b)

c 3(b-2)^2

d.(c-5)(1+2x)

Step-by-step explanation:

5 0

3 years ago

Assume that random guesses are made for seven multiple choice questions on an SAT test, so that there are nequals7 trials, eac

Ket [755]

Answer:

$P(X < 4)=0.1335+0.3115+0.3115+0.1730=0.9295$

Step-by-step explanation:

Question assumed: Find the probability that the number x of correct answers is fewer than 4.

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=7, p=0.25)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(X < 4)=P(X=0)+P(X=1)+P(X=2)+P(X=3)$

$P(X=0)=(7C0)(0.25)^0 (1-0.25)^{7-0}=0.1335$

$P(X=1)=(7C1)(0.25)^1 (1-0.25)^{7-1}=0.3115$

$P(X=2)=(7C2)(0.25)^2 (1-0.25)^{7-2}=0.3115$

$P(X=3)=(7C3)(0.25)^3 (1-0.25)^{7-3}=0.1730$

$P(X < 4)=0.1335+0.3115+0.3115+0.1730=0.9295$

3 0

4 years ago

If f(x) = 3x^2 - 4x + 5 and g(x) = 2x^2 + 2, find f(x) – g(x). Answer: x^2 - 4x + 3

Nadusha1986 [10]

Answer:

f(x) – g(x) = x^2 - 4x + 3

Step-by-step explanation:

f(x) = 3x^2 - 4x + 5 and g(x) = 2x^2 + 2,

f(x) – g(x) = 3x^2 - 4x + 5 - ( 2x^2 + 2)

Distribute the minus sign

f(x) – g(x) = 3x^2 - 4x + 5 - 2x^2 - 2

Combine like terms

f(x) – g(x) = x^2 - 4x + 3

5 0

3 years ago

The band sold $498 worth of tickets for their spring concert. Adult tickets cost $5 each and student tickets cost $3 each. If th

saw5 [17]

Let: A = adult tickets; S = student tickets

a. 498 = 5A + 3S
118 = A + S

b. S = 118 - A
498 = 5A + 3(118 - A)
498 = 5A + 354 - 3A
498 - 354 = 2A
144 = 2A
A = 72

118 = S + A
118 = 72 + S
118 - 72 = S
S = 46

c. Therefore, there were 72 adult tickets and 46 student tickets sold.

5 0

4 years ago