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3 years ago

If G varies inversely as r, and G = 18 when r= 4, find G when r= 6

1 answer:

3 0

The model to use here is y = k/x.

If g =18 when r = 4, then 18 = k/4. Solving for k, k = 72.

Then g = 72/r. If r = 6, g = 72/6 = 12 (answer)

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X-4y=7 -6x-3y=12 how do i solve by substitution

Dafna1 [17]

Answer:

x = 15

y = 2

Step-by-step explanation:

X-4y=7 | ×6 |

-6x-3y=12 | ×1 |

6x - 24y = 42

-6x - 3y = 12

___________+

27y = 54

y = 54/27

y = 2

x - 4y = 7

x - 4(2) = 7

x - 8 = 7

x = 7 + 8

x = 15

3 0

3 years ago

In a sale, normal prices are reduced by 17%. The normal price of a washing machine is reduced by £42.50

Misha Larkins [42]

Answer: The original price of washing machine is $250.

Step-by-step explanation:

Since we have given that

Rate of decline in normal prices = 17%

Amount of normal price reduced by = $42.50

Let the original price be x

According to question,

$\frac{17}{100}\times x=42.50\\\\x=\frac{100}{17}\times 42.50\\\\x=\$250$

Hence, The original price of washing machine is $250.

8 0

3 years ago

Here are the endpoints of the segments BC, FG, and JK.<br> B, −67

yulyashka [42]

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}$

$F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}$

$JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill$

4 0

2 years ago

In a triangle, the base and height are in the ratio 6:5. If the area of the triangle is 135 sq cm, calculate the length of the b

Eduardwww [97]

Answer:

use the firmula

area of triangle =1/2b×h

Step-by-step explanation:

let the ratio be 6x and 5x

6x+5x=135
now solve this
this may help you

8 0

3 years ago

4 × (1,351 - 381)

Dovator [93]

The answer is C.

The expression is telling you to multiply the parenthesis times four. When you multply two numbers, $a \times b$ , it means that you're considering $a$ "copies" of $b$ , or if you prefer, $b$ repeated $a$ times.

So, you have

$2 \times (1.351 - 381)$ <- this is twice as much as the parenthesis

$3 \times (1.351 - 381)$ <- this is three times as much as the parenthesis

$4 \times (1.351 - 381)$ <- this is four times as much as the parenthesis

6 0

3 years ago

Read 2 more answers