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Ulleksa [173]
3 years ago
7

Write a division problem that will have a two digit quotient and another division problem that will have a 3 digit quotient. Exp

lain how you chose the divisors and dividends
Mathematics
1 answer:
il63 [147K]3 years ago
5 0
48 divided by 2 = 24
3333 divided by 6 = 555.5
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If Keegan haas 12 nickels and dimes in his pocket and they have a combined value of 80 cents how many of each coin does he have
Firdavs [7]
12 × 5 = 60
12 nickels
10 × 2 = 20
2 dimes
60 + 20 = 80
5 0
3 years ago
Triangle m is similar to triangle n. Triangle m has two angles with measures of 32 degrees and 93 degrees. Which two angle measu
Ray Of Light [21]
We know that

If two triangles are similar the corresponding angles must be congruent.
therefore
triangle N must have an angle of 32° and 93°

the answer is
angle measure of 32° and angle measure of 93°
3 0
3 years ago
Quadrilateral EFGH is on a coordinate plane. Segment FG is on the line 2x − y = −3, and segment EH is on the line 2x − y = 1. Wh
umka2103 [35]

Answer:

They have the same slope of 2 and are, therefore, parallel.

Step-by-step explanation:

Given: Equation of FG is 2x-y=-3 and equation of EH is 2x-y=1

To find: Relation between segments FG and EH

Solution:

Slope of a line describes its direction and the steepness.

Two lines are said to be parallel if their slopes are equal.

2x-y=-3

Differentiate with respect to x

2-y'=0\\y'=m_1=2

where m_1 denotes the slope of the line FG

2x-y=1

Differentiate with respect to x

2-y'=0\\y'=m_2=2

where m_2 denotes slope of line EH

As m_1=m_2=2, lines are parallel

4 0
3 years ago
If csc theta = 8/7, which equation represents (cot theta) ?
Paul [167]

Out of the given choice, the equation represents \cot \theta=\frac{\sqrt{15}}{7}.

Answer: Option B

<u>Step-by-step explanation:</u>

We know, \csc \theta=\frac{1}{\sin \theta}

                \sin \theta=\frac{1}{\csc \theta}

Given data:

                \csc \theta=\frac{8}{7}

So, now sin theta can express as

                \sin \theta=\frac{7(\text { opposite })}{8(\text { Hypotenuse })}

Sin theta defined by the ratio of opposite to the hypotenuse. In general, the adjacent can be calculated by,

           \text {(opposite) }^{2}+(\text { adjacent })^{2}=(\text {Hypotenuse})^{2}

          7^{2}+(\text { adjacent })^{2}=8^{2}

         (\text {adjacent})^{2}=8^{2}-7^{2}=64-49=15

Taking square root, we get

           \text { adjacent }=\sqrt{15}

Also, we know the formula for cot theta,

         \cot \theta=\frac{1}{\tan \theta}=\frac{1}{\left(\frac{\sin \theta}{\cos \theta}\right)}=\frac{\cos \theta}{\sin \theta}

Cos theta denoted as the ratio of adjacent to the hypotenuse.

           \cos \theta=\frac{\sqrt{15}(\text {Adjacent})}{8(\text {Hypotenuse})}

Therefore, find now as below,

           \cot \theta=\frac{\left(\frac{\sqrt{15}}{8}\right)}{\left(\frac{7}{8}\right)}=\frac{\sqrt{15}}{8} \times \frac{8}{7}=\frac{\sqrt{15}}{7}

7 0
3 years ago
Read 2 more answers
Paul travels from Rye to Eston at an average speed of 90km/h. He travels for T hours. Mary makes the same journey at an average
blsea [12.9K]
Total distance covered;
For Paul;
sxt=distance
90*t= d
For mary;
s*t=d
70*(t+1)=d
70t+70=d

Since they cover same distance;
70t+70=90t
Putting like terms together;
70=90t-70t
70=20t
t=70/20
t= 3 and 1/2 hours
6 0
3 years ago
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