Ask question

Ask question

All categories

4 years ago

11

What equation results when you cross-multiply 17/d = 51/21

1 answer:

exis [7]4 years ago

4 0

Answer:

357 = 51d

Step-by-step explanation:

17/d = 51/21

Using cross products

17*21 = 51*d

357 = 51d

solving

357/51 = 51d/51

7 =d

You might be interested in

What is the slope if you have (2,1) and (4,4)?<br><br><br>*Ineed this quickly as possible!-Thx

Schach [20]

$(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{4}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{2}}}\implies \cfrac{3}{2}$

7 0

2 years ago

Read 2 more answers

Which of the following is in order from smallest to largest?

kirill115 [55]

Answer:

-5,-8,-10,1,7

Step-by-step explanation:

6 0

3 years ago

A video game has been developed whereby the player must earn a certain number of experience points before progressing to the nex

Katyanochek1 [597]

61 experience points

4 0

4 years ago

Quadrilateral ABCD has vertices A(1,0) B(5,0) C (7,2) D(3,2). Use slope to prove that ABCD is a parallelogram.

Galina-37 [17]

Answer:

$AD \parallel BC$

$AB \parallel CD$

Step-by-step explanation:

The vertices of quadrilateral ABCD are A(1,0) B(5,0) C (7,2) D(3,2).

The slope of side AB is

$M_{AB}=\frac{0-0}{5-1} =\frac{0}{4}=0$

The slope of side BC is

$M_{BC}=\frac{2-0}{7-5} =\frac{2}{2}=1$

The slope of side CD is

$M_{CD}=\frac{2-2}{3-7} =\frac{0}{-4}=0$

The slope of AD is

$M_{AD}=\frac{2-0}{3-1} =\frac{2}{2}=1$

$AD \parallel BC$

$AB \parallel CD$

We see that the opposite sides of the quadrilateral ABCD are equal.

Hence the quadrilateral is a parallelogram

4 0

3 years ago

Help me plz :))))) <br>

Vika [28.1K]

Answer:

2 3 1 3

Step-by-step explanation:

7 0

3 years ago