3 years ago

Can you sub to my youttube channel pls, its called Yakobu, im trying to get to 110 subs :)

Mathematics

2 answers:

Alenkinab [10]3 years ago

7 0

Answer: YES I WILL SUB

mixas84 [53]3 years ago

7 0

Answer:

UwU ok ill sub for you........

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A³b² a²b simplify the following expression

liberstina [14]

Answer:

$a^{5}$ $b^{3}$

Step-by-step explanation:

The law of indices can be used to simplify mathematical expressions involving arithmetical operation on variables with powers.

$a^{m}$ x $a^{n}$ = $a^{(m+n)}$

Thus, the given expression can be simplified as follows:

a³b² a²b = a³ x a² x b² x $b^{1}$

= $a^{3+2}$ x $b^{2+1}$

= $a^{5}$ $b^{3}$

Thus,

a³b² a²b = $a^{5}$ $b^{3}$

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3 years ago

To solve the inequality m/-7<(or equal to) 14 , what should be done to both sides?

Marizza181 [45]

Answer:

$\large\boxed{m\geq-98}$

Step-by-step explanation:

$\dfrac{m}{-7}\leq14\\\\-\dfrac{m}{7}\leq14\qquad\text{change the signs}\\\\\dfrac{m}{7}\geq-14\qquad\text{multiply both sides by 7}\\\\7\!\!\!\!\diagup^1\cdot\dfrac{m}{7\!\!\!\!\diagup_1}\geq(7)(-14)\\\\m\geq-98$

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3 years ago

Read 2 more answers

i have 6 digits. One of my 3s is worth 300.000. The other is worth 1/10 as much. My 6 is worth 600.The rest of my digits are zer

motikmotik

The way you wrote the problem makes the answer 330,600. I think your decimals were meant to be commas. If I am wrong, please forgive me.

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3 years ago

When 5 randomly selected people all have the same birth month of March.

Doss [256]

Answer:

I know 4 people that are all really close friends and all have birthdays in march.

Step-by-step explanation:

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3 years ago

What is the answer of this problem

Goshia [24]

second answer to the left

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