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2 years ago

5

Starting at the top of a square pyramid and make a vertical slice cutting pyramid in half what is the shape of the newly-exposed

section
I really appreciate it if you can check my answer. I I think it’s a triangle.

1 answer:

puteri [66]2 years ago

5 0

Answer: Triangle

Step-by-step explanation: If you cut it vertically, the base is changed into a triangle.

Hope this helps!

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Part 4: Use the information provided to write the vertex formula of each parabola.

sergey [27]

Answer: 1. x = (y - 2)² + 8

$\bold{2.\quad x=-\dfrac{1}{2}(y-10)^2}+1$

3. y = 2(x +9)² + 7

<u>Step-by-step explanation:</u>

Notes: Vertex form is: y =a(x - h)² + k or x =a(y - k)² + h

(h, k) is the vertex
point of vertex is midpoint of focus and directrix: $\dfrac{focus+directrix}{2}$

$\bullet\quad a=\dfrac{1}{4p}$

p is the distance from the vertex to the focus

1)

$focus = \bigg(\dfrac{-31}{4},2\bigg)\qquad directrix: x=\dfrac{-33}{4}\\\\\text{Since directrix is x, then the x-value of the vertex is:}\\\\\dfrac{focus+directrix}{2}=\dfrac{\frac{-31}{4}+\frac{-33}{4}}{2}=\dfrac{\frac{-64}{4}}{2}=\dfrac{-16}{2}=-8\\\\\text{The y-value of the vertex is given by the focus as: 2}\\\\\text{vertex (h, k)}=(-8,2)$

Now let's find the a-value:

$p=focus-vertex\\\\p=\dfrac{-31}{4}-\dfrac{-32}{4}=\dfrac{1}{4}\\\\\\a=\dfrac{1}{4p}=\dfrac{1}{4(\frac{1}{4})}=\dfrac{1}{1}=1$

Now, plug in a = 1 and (h, k) = (-8, 2) into the equation x =a(y - k)² + h

x = (y - 2)² + 8

***************************************************************************************

2)

$focus = \bigg(\dfrac{1}{2},10\bigg)\qquad directrix: x=\dfrac{3}{2}\\\\\text{Since directrix is x, then the x-value of the vertex is:}\\\\\dfrac{focus+directrix}{2}=\dfrac{\frac{1}{2}+\frac{3}{2}}{2}=\dfrac{\frac{4}{2}}{2}=\dfrac{2}{2}=1\\\\\text{The y-value of the vertex is given by the focus as: 10}\\\\\text{vertex (h, k)}=(1,10)$

Now let's find the a-value:

$p=focus-vertex\\\\p=\dfrac{1}{2}-\dfrac{2}{2}=\dfrac{-1}{2}\\\\\\a=\dfrac{1}{4p}=\dfrac{1}{4(\frac{-1}{2})}=\dfrac{1}{-2}=-\dfrac{1}{2}$

Now, plug in a = -1/2 and (h, k) = (1, 10) into the equation x =a(y - k)² + h

$\bold{x=-\dfrac{1}{2}(y-10)^2}+1$

***************************************************************************************

3)

$focus = \bigg(-9,\dfrac{57}{8}\bigg)\qquad directrix: y=\dfrac{55}{8}\\\\\text{Since directrix is y, then the y-value of the vertex is:}\\\\\dfrac{focus+directrix}{2}=\dfrac{\frac{57}{8}+\frac{55}{8}}{2}=\dfrac{\frac{112}{8}}{2}=\dfrac{14}{2}=7\\\\\text{The x-value of the vertex is given by the focus as: -9}\\\\\text{vertex (h, k)}=(-9,7)$

Now let's find the a-value:

$p=focus-vertex\\\\p=\dfrac{57}{8}-\dfrac{56}{8}=\dfrac{1}{8}\\\\\\a=\dfrac{1}{4p}=\dfrac{1}{4(\frac{1}{8})}=\dfrac{1}{\frac{1}{2}}=2$

Now, plug in a = 2 and (h, k) = (-9, 7) into the equation y =a(x - h)² + k

y = 2(x +9)² + 7

4 0

3 years ago

Julio has started his very own floral business. He sells centerpieces for $19.50 each. His fixed costs are $500 per month, and e

Phantasy [73]

The total cost, C, is the sum of the cost to produce the centerpieces and the fixed cost. The equation for C is C = 8n + 500.

The total revenue, R, of Julio's floral business is the product of the cost per centerpiece and the number of centerpieces sold. The equation for R is R = 19.50n.

8 0

3 years ago

Read 2 more answers

/ has vertices at (–5, 1) and (–3, 7). After a transformation, the image had endpoints at (3, –1) and (5, 5). Describe the trans

Pie

1st point: ( -5+8. 1-2 ) = ( 3, -1 )
2nd point: ( -3+8, 7-2 ) = ( 5, 5 )
Answer: C) translation right 8 units and down 2 units.

3 0

2 years ago

Please help me asap I am in class

lions [1.4K]

2: 2/3; 3: 3/4; 4: 1/4; 5: 1/3; 6: 1/4; 7: 4/5; 8: 5/6-3/6=1/3

4 0

2 years ago

Is it possible that the image of a point after a reflection could be the same point as the preimage?

Vera_Pavlovna [14]

Yes, it is possible. For example, let's say that point A is (0,4) and there's a reflection over the y-axis, then point A would still be (0,4).

3 0

3 years ago