Answer is 54 °C.
<em>Explanation;</em>
We can simply use heat equation
Q = mcΔT
Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).
Let's assume that the initial temperature is T.
Q = 5.53 × 10⁵ J
m = 2850 g
c = 4.186 J/g °C
ΔT = (100 - T) °C <em>Since the water is boiling, the final temperature is 100 °C.</em>
By applying the equation,
5.53 × 10⁵ J = 2850 g x 4.186 J/g °C x (100 - T) °C
(100 - T) °C = 5.53 × 10⁵ J / (2850 g x 4.186 J/g °C )
(100 - T) °C = 46.35 °C
T = 100 - 46.35 C = 53.65 °C
≈ 54 °C
Answer:
The phenomenon of plasmolysis.
Explanation:
When cells of Elodea are placed in a salt solution the phenomenon of plasmolysis occurs and the water will start to move out from the cell. The concentration of salts in the cell will get high due to the diffusion of salt molecules inward. The organelles will look like as they are centered to the cell by hook.
<span>Mantle convection is the slow creeping motion of Earth's rocky mantle caused by convection currents carrying heat from the interior of the earth to the surface. It is one of 3 driving forces that causes tectonic plates to move around the Earth's surface.</span>
1. Synthesis reaction
2. Decomposition reaction
3. Double replacement reaction
4. Combustion reaction
5. Single replacement reaction
Answer:
- Sn²⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰
- Ti⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 4f¹⁴ 6s² 5d¹⁰
- As⁺³ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
Explanation:
The <em>electron configuration</em> indicates the way the electrons of an atom or ion are structured.<u> In the case of cations</u>, by knowing the electronic configuration of the atom (which is neutral), we can find out the cations' configuration by substracting <em>n</em> outermost electrons, where <em>n</em> is the charge of the cation.
Mg⁰ ⇒ [Ne] 3s² = 1s² 2s² 2p⁶ 3s². Thus
Mg⁺² ⇒ [Ne] = 1s² 2s² 2p⁶.
In a similar fashion, the answers are:
Sn²⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰
K⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶
Al³⁺ ⇒ 1s² 2s² 2p⁶
Ti⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 4f¹⁴ 6s² 5d¹⁰
As⁺³ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
