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DENIUS [597]
2 years ago
13

What happens to carbon in plants when the plants die.

Chemistry
1 answer:
Korvikt [17]2 years ago
4 0

Answer:

Released into the atmosphere

Explanation:

The carbon that the plant had been storing when it was alive, would be released upon death into the soil

You might be interested in
Name the type of chemical reaction : CaO(s) + H2O(l) -----------Ca(OH)2(aq)
Anna [14]
It is called Synthesis reaction
5 0
3 years ago
Equal but opposite forces acting on an object results in what?
forsale [732]

Answer:

Action given and reaction taken

Also known as

Newton's third law of motion

Explanation:

An action will be done such as bouncing a ball on the wall

- You throw the ball (Action)

- The ball bounces back (Reaction)

Hope this Helps

3 0
2 years ago
Which carboxylic acid is used to prepare the ester shown?
valentinak56 [21]

Answer:

B

Explanation:

The general equation for the reaction of a carboxylic acid with an alkanol to form an ester is shown below;

RCOOH + ROH ------> RCOOR + H2O

Hence; the reactant carboxylic acid can only be the compound (CH3)2-CH-CH2-COOH in accordance with the general reaction equation shown above.

Hence the reaction is;

(CH3)2-CH-CH2-COOH + CH3-CH2OH -------> CH3CH2 OCO-CH2-CH-(CH3)2

3 0
3 years ago
HELPPP<br>yall please help my sister won't help me ​
ira [324]

\text{H}_3\text{PO}_4  + 3\text{KOH}  \longrightarrow \text{K}_3 \text{PO}_4     +3\text{H}_2 \text{O}\\\\10\text{Na} +2 \text{NaNO}_3  \longrightarrow 6\text{Na}_2 \text{O} + \text{N}_2\\\\\  2\text{H}_3 \text{PO}_4 + 3\text{Mg(OH)}_2 \longrightarrow \text{Mg}_3(\text{PO}_4)_2+6\text{H}_2 \text{O}\\\\2\text{Al(OH)}_3 + 3\text{H}_2 \text{CO}_3 \longrightarrow \text{Al}_2(\text{CO}_3)_3 + 6\text{H}_2 \text{O} \\\\2\text{C}_6\text{H}_6+15\text{O}_2 \longrightarrow 12\text{CO}_2 +6\text{H}_2 \text{O}\\

\text{Pb(OH)}_2 +2\text{HCl} \longrightarrow \text{PbCl}_2 +2 \text{H}_2 \text{O}

2\text{Mn} + 6\text{HI} \longrightarrow 3 \text{H}_2+2\text{MnI}_3

3 0
3 years ago
A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4
Harman [31]
Na₃PO₄ -----> 3Na(+) + PO₄(3-)
y-y.......................3y...........y

3y = 1.2
y = 0,4M

Na₃PO₄ -----> 3Na(+) + PO₄(3-)
0,4-0,4..............1,2..........0,4
0.........................1,2..........0,4

C = n/V
n = C×V
n = 0,4×0,65L
n = 0,26 mol Na₃PO₄

mNa₃PO₄: (23×3)+31+(16×4) = 164 g/mol

164g ----- 1 mol
Xg -------- 0,26 mol
X = 164×0,26
X = 42,64g Na₂SO₄
5 0
3 years ago
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