A bouquet of lilies and tulips has 12 flowers. lilies cost $3 each and tulips cost $2 each the bouquet cost $32. write and solve
1 answer:
Answer:
Let x represents the number of lilies and y represents the number of tulips in the bouquet.
As per the statement:
A bouquet of lilies and tulips has 12 flowers.
⇒x+y = 12 .....[1]
It is also given that lilies cost $3 each and tulips cost $2 each the bouquet cost $32.
⇒ .....[2]
Multiply equation [1] by 3 we get;
3x+ 3y = 36 .....[3]
Subtract equation [2] from [3] we get;
Combine like terms;
Substitute the value of y in [1] we get;
x + 4 = 12
Subtract 4 from both sides we get;
x = 8
Therefore, the number of lilies are 8 and the number of tulips are 4
You might be interested in
Answer:
<em>First even integer: 6</em>
Step-by-step explanation:
<u>Inequalities</u>
Assume x is the first even integer. The next integer is x+2, and the last integer ix x+4.
The condition states that the sum of the first and the second number is 15 less than three times the third. This takes us to the inequality:
Operating:
Subtracting 2 and 2x:
Simplifying:
Solving:
x>5
There are infinitely many solutions. For example, for x=6 (first even number into the solution interval):
First integer: 6
Second integer: 8
Third integer: 10
There are other solutions, like 20,22,24 but the first set is 6,8,10.