Question

Which equation shows a valid, practical step in solving

Answer 1

For this case we have the following equation:

$\sqrt [4] {2x-8} + \sqrt [4] {2x + 8} = 0$

If we subtract both sides of the equation $\sqrt [4] {2x + 8}$ we have:

$\sqrt [4] {2x-8} = - \sqrt [4] {2x + 8}$

To eliminate the radical we raise both sides of the equation to the fourth power:

$(\sqrt [4] {2x-8}) ^ 4 = (- \sqrt [4] {2x + 8}) ^ 4$

Answer:

Option D