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tester [92]
3 years ago
5

Secx-cosx/tanx=___? Explain pls ...?

Mathematics
1 answer:
harkovskaia [24]3 years ago
6 0
\frac{secx- cos x}{tan x}= \\ = \frac{ \frac{1}{cos x} -cos x}{ \frac{sinx}{cos x}}= \\ = \frac{ \frac{1-cos ^{2} x}{cos x} }{ \frac{sinx}{cos x} }= \\ = \frac{sin ^{2} x}{sin x}=
= sin x
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