<span>
</span>
<span>x+<span>(x+2)</span>+<span>(x+4)</span>=48</span>
3x+6=48
Minus 6 to both sides
<span>3x=42</span>
Divide 3 to both sides
<span>x=14</span>
Get the next two integers
<span>x,x+2,x+4 or 14,16,<span>18 = 48 is you Answer</span></span>
Answer:
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
By:
I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
Answer:
a
Step-by-step explanation:
I don’t know too can someone help me as welll???
So let me give you the answer with procedure so that you can understand it better:
Let x = Number
<span>Product of 9 and Number:</span>
<span>9x </span>
<span>is 12 less than 3 times that number. So: </span>
<span>3x - 12 </span>
<span>Set them equal and solve for x like this:</span>
<span>9x = 3x - 12 </span>
<span>6x = -12 </span>
<span>x = -2
</span>I hope this is very useful for you