There are 20 children in the cast of a class play, and 8 of the children are boys. of the boys, 4 have a speaking part in the pl
ay, and of the girls, 8 do not have a speaking part in the play. if a child from the cast of the play is chosen at random, what is the probability that the child has a speaking part?a. 2/5b. 1/2c. 3/5d. 3/4
<span>it all looks confusing when we try to juggle with all those numbers in the head. The problem can be solved systematically by constructing a contingency table. </span>role/gender B G total speaking...... 4 4 8 <span> silent............ 4 8 12 total............. 8 12 20 </span>Probability of a child having a speaking part is therefore (4+4)/20=8/20=2/5 a. 2/5
In a division problem, the number being divided into pieces is the dividend. The number by which the dividend is divided is called the divisor. And the answer to the division problem is the quotient.
The function f(x) shows the number of cell tower users after "x" years from the year 2010.
Then, the dependent varible of the function f(x) are the number of cell tower users after x years from 2010, and the independent variable of this function, "x", are the years that have passed since 2010, included 2010.
This means that the independent variable should take the values of the years from 2010, which represent the domain (values that x variable can take), that are all the years between 2010 and 2019 (which is the present year).
