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Alecsey [184]
3 years ago
13

making 10 pounds of Apple Jam requires five pounds of Apple how many pounds of Apple are needed to make eight pounds of apple ja

m
Mathematics
2 answers:
ser-zykov [4K]3 years ago
7 0
10 pounds jam=5 pounds apples
therefor divide both sides by 5
2 poinds jam=1 pound apple
1 pound jam=1/2 pound apple

8 pounds jam=8 times 1/2 pound apple
8 times 1/2=4

answe is 4 pounds apples
____ [38]3 years ago
5 0
80 the answer is 80 or eighth over ten (hope this helps!:)
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Camila is putting together gift bags for nurses at a local clinic. Each of the 5 gift bags contains 'x' cookies. Camila adds 3 m
Vladimir [108]

Answer:

A- X= 20÷5-3

B- 20÷5=4; 4-3=1

C- X=1

Step-by-step explanation:

Okay, well we have to work backwards. 20 cookies, and she makes 5 bags. We need to find out what 'x' means. To do that, we take 20 cookies and divide it by 5. 4 cookies. Then we want to take 3 cookies out of each bag to find out how many cookies she first put in. 1 cookie.

Let's check:

bag 1:

o (one cookie)

bag 2:

o (one cookie)

bag 3:

o (one cookie)

bag 4:

o (one cookie)

bag 5:

o (one cookie)

Now we have 15 cookies left. Now let's put 3 in each:

bag 1:

o (one cookie)

v v v ( three cookies)

bag 2:

o (one cookie)

v v v ( three cookies)

bag 3:

o (one cookie)

v v v ( three cookies)

bag 4:

o (one cookie)

v v v ( three cookies)

bag 5:

o (one cookie)

v v v ( three cookies)

Now we have no cookies left, and we put 4 cookies in each. (o representing the first cookie, v representing the next three cookies)

7 0
2 years ago
Read 2 more answers
Zamira and Courtney share a 16 oz box of cereal. By the end of the week, Zamira has eaten 38 of the box, and Courtney has eaten
12345 [234]

Answer:

12/25 ths of the box is left.

Step-by-step explanation:

I'm assuming you mean 14% and 38%

If so then the first thing you'd do is put 38 and fourteen over 100 such as:

38/100 and 14/100.  You do that because since its a percentage, its the same as the number of that percentage over 100.

Since you now have like terms, you can add them together, in which you add the two numerators (top row), but leaving the denominator (bottom row) the same, and it would give you:

52/100

What you want to do after that is simplify it. Once you simplify it, the simplified version of this is technically still the same as the non-simplified version, just easier to use.

Once you simplify it once, you will get:

26/50 and then if you simplify it again, you'll get 13/25

KEEP IN MIND that this is the amount that HAS BEEN EATEN ALREADY.

After that, you wan to subtract your part from your whole meaning you'd subtract: 25/25 - 13/25

Going back to earlier, you subtract the numerator and leave the denominator the same ONLY because they have like terms(The DENOMINATORS match)

After subtracting, you will get an answer of 12/25ths, which cannot be further simplified either.

Hope this helped!

4 0
2 years ago
Find the nth term of the following sequence: 7, 13, 19, 25,
Natalija [7]
The answer of the next term is 31
8 0
2 years ago
Read 2 more answers
Lizzie rolls two dice. What is the probability that the sum of the dice is:
zhenek [66]

Answer:

A.\ \dfrac{1}{3}\\B.\ \dfrac{5}{12}\\C.\ \dfrac{7}{36}\\

Step-by-step explanation:

Total outcomes possible: 36

A. Divisible by 3

Possible options are:

3, 6, 9 and 12.

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Possible outcomes for 9 are: {(3,6), (4,5), (5,4),(6,3)} Count 4

Possible outcomes for 12 are: {(6,6)} Count 1

Total count = 2 + 5 + 4 + 1 = 12

Probability of an event E can be formulated as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A)  = \dfrac{12}{36} = \dfrac{1}{3}

B. Less than 7:

Possible sum can be 2, 3, 4, 5, 6

Possible cases for sum 2: {(1,1)}  Count 1

Possible cases for sum 3: {(1,2), (2,1)}  Count 2

Possible cases for sum 4: {(1,3), (3,1), (2,2)}  Count 3

Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)}  Count 4

Possible cases for sum 6: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Total count = 1 + 2 + 3 + 4 + 5 = 15

P(B)  = \dfrac{15}{36} = \dfrac{5}{12}

C. Divisible by 3 and less than 7:

P(A \cap B) = \dfrac{n(A\cap B)}{\text{Total Possible outcomes}}

Here, common cases are:

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

P(A \cap B) = \dfrac{7}{\text{36}}

5 0
2 years ago
Solve each system by elimination.<br> 10x-6y=-8<br> -10x+6y=8
Step2247 [10]

Answer:

Infinitely Many Solutions

Step-by-step explanation:

10x-6y=-8\\-10x+6y=8\\\0 = 0\\

4 0
2 years ago
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