Answer:
(4,3)
Step-by-step explanation:
Given
x^2+y^2=25
x-y^2=-5
In order to solve the equations, from equation 2 we get
-y^2= -5-x
y^2=5+x
Putting the value of y^2 in equation 1
x^2+5+x=25
x^2+5-25+x=0
x^2+x-20=0
x^2+5x-4x-20= 0
x(x+5)-4(x+5)=0
(x+5)(x-4)=0
So
x+5=0 x-4=0
x=-5 x=4
Now for x=-5
x^2+y^2=25
(-5)^2+y^2=25
25+y^2=25
y^2=25-25
y^2=0
so Y=0
And for x = 4
x^2+y^2=25
(4)^2+y^2=25
16+y^2=25
y^2=25-16
y^2=9
y= ±3
So the solution to the system of equations is
(-5,0) , (4,3), (4,-3)
The only solution that belongs to first quadrant is (4,3)
Answer:
In the ATTACHMENT
Step-by-step explanation:
For the first one, you can plug in multiple numbers of any kind for 
and start to form you line.
For the second one, know that the 
line is always horizontal. Find -3 on the plot that would be on the 
and put that horizontal line on it.
<em>Hope this helps!!</em>
P² - 12 p - 13 = 0
Δ = ( -12)² - 4 ( 1 * - 13)
Δ = 144 + 52
Δ = 196 = 14²
x₁ = (- ( -12) + 14 ) / 2 = 26/2 = 13
x₂ = ( - ( -12) - 14) /2 = - 2 /2 = - 1
S = 13
9 - 18
5 - 10
1 - 2
Work —
First line:
y = 2 (9)
y = 18
Second line:
10 = 2x
5 = x
Third line:
y = 2 (1)
y = 2
Well i’m not sure on this but i got 18 for my answer instead of 10 so if u need any mode help im here
