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givi [52]
3 years ago
12

What is 978 times 3635??

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
5 0
978 x 3635 = 3555030

hope this helps you

ASHA 777 [7]3 years ago
3 0
978 X 3635 = 3555030

I hope this helps! :)
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55

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What is the solution to this equation 5x -8(x + 5)= 6-3x
Solnce55 [7]

Answer:

no solution

Step-by-step explanation:

5x - 8(x + 5) = 6 - 3x

Remember to follow PEMDAS. Note the equal sign, what you do to one side, you do to the other.

First, distribute -8 to all terms within the parenthesis

-8(x + 5) = (-8)(x) + (-8)(5) = -8x - 40

5x - 8x - 40 = 6 - 3x

Isolate the variable (x). Add 3x & 40 to both sides

5x - 8x (+3x) - 40 (+40) = 6 (+40) - 3x (+3x)

5x - 8x + 3x = 6 + 40

Simplify. Combine like terms

(5x - 8x + 3x) = (6 + 40)

0 = 46 ; False 0 ≠ 46 ∴ no solution is your answer

~

8 0
3 years ago
When two six-sided dice are rolled, there are 36 possible outcomes. Find the probability that the sum is not 5.
zaharov [31]

Answer:

p(Not\ 5) = \frac{8}{9}

Step-by-step explanation:

Given:

Txo six-sided dice are rolled.

Total number of outcomes n(S) = 36

We need to find the probability that the sum is not equal to 5 p(Not 5).

Solution:

Using probability formula.

P(E)=\frac{n(E)}{n(S)}  ----------------(1)

Where:

n(E) is the number of outcomes favourable to E.

n(S) is the total number of equally likely outcomes.

The sum of two six-sided dice roll outcome is equal to 5 as.

Outcome as 5: {(1,4), (2,3), (3,2), (4,1)}

So, the total favourable events n(E) = 4

Now, we substitute n(E) and n(s) in equation 1.

P(5)=\frac{4}{36}

p(5) = \frac{1}{9}

Using formula.

p(Not\ E) + p(E) = 1

p(Not\ 5) + p(5) = 1

Now we substitute p(5) in above equation.

p(Not\ 5) + \frac{1}{9} = 1

p(Not\ 5) = 1-\frac{1}{9}

p(Not\ 5) = \frac{9-1}{9}

p(Not\ 5) = \frac{8}{9}

Therefore, the sum of two six-sided dice roll outcome is not equal to 5.

p(Not\ 5) = \frac{8}{9}

6 0
3 years ago
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