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sweet-ann [11.9K]
3 years ago
14

If a quadrilaterals diagonals bisect its vertices, what kind of quadrilateral must it be?

Mathematics
1 answer:
Blababa [14]3 years ago
6 0
<span>Option A, This type of quadrilaterals is a polygon and is called Rhombus because all sides are equal, each pair of acute and obtuse angles are opposite, their diagonals are distinct and perpendicular to each other, bisectors and have an inscribed circumference.</span>
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What is the function rule for the line?
ludmilkaskok [199]

A: Slope:  

2

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y-intercept:  

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6 0
2 years ago
Which of the following is not an undefined term?<br><br> point<br> ray<br> line<br> plane
mina [271]
I think that it is point. A point is very precise

7 0
3 years ago
Read 2 more answers
two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe
sveta [45]

Applying the required <em>rule </em>or <em>theorem</em>, it can be concluded that the second biker is <u>farther</u> from the <em>parking lot</em>. The distance of the bikers to the <em>parking lot</em> are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The <u>path</u> of travel of both bikers would form a triangle. Applying the <u>Pythagoras</u> theorem to the path of the <em>first</em> biker would give his <u>distance</u> from the starting point. While applying the <u>cosine</u> rule to the path of <em>second</em> rider would gives his <u>distance</u> to the starting point.

Thus,

a. <u>To determine the distance of the first biker from the parking lot.</u>

Let the required <em>distance </em>be represented by x. Applying the Pythagoras theorem, we have:

hyp^{2} = adj 1^{2} + adj 2^{2}

x^{2} = 8^{2} + 15^{2}

   = 64 + 225

   = 289

x = \sqrt{289}

  = 17

x = 17 km

Thus, the <u>first</u> biker is 17.0 km from the <em>starting</em> point.

b. <u>To determine the distance of the second biker from the parking lot.</u>

Let the required <em>distance</em> be represented by x. So that applying the cosine rule, we have:

c^{2} = a^{2} + b^{2} - 2ab Cos θ

x^{2} = 8^{2} + 15^{2} - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

x^{2} = 289 + 120

   = 409

x = \sqrt{409}

 = 20.2237

x = 20.22 km

Thus, the <u>second</u> biker is 20.22 km from the <em>starting</em> point.

Therefore, the second biker is <u>farther</u> from the <em>parking lot</em>.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

7 0
2 years ago
Miguel bikes 23 km per hour and starts at mile 10. Gabby bikes 28 km per hour and starts at mile 0. Which system of linear equat
7nadin3 [17]
The correct answer is D) Miguel:  d=23t+10, Gabby d=28t

We multiply the speed of each person by t, the amount of time.  This is where the 23t in Miguel's equation and the 28t in Gabby's equation come from.  The starting point is added to this, which leads to 23t+10 and 28t+0 or 28t.
8 0
3 years ago
Read 2 more answers
Say that a supplier claims they are 99% confident that their products will be in the interval of 50.02 to 50.38. You take sample
nydimaria [60]

Answer:

The supplier becomes less accurate than they otherwise would have tried to claim. A further explanation is below.

Step-by-step explanation:

According to the provider, this same width of that same confidence interval would be as follows:

= 50.38 - 50.02

= 0.36

Depending on the input observed, the width including its confidence interval would be as follows:

= 50.39 - 50.01

= 0.38

As even the width of that interval again for survey asserted > the width including its confidence interval according to the provider's statement, we could conclude that such is the appropriate reaction.

3 0
3 years ago
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