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sweet-ann [11.9K]

3 years ago

14

If a quadrilaterals diagonals bisect its vertices, what kind of quadrilateral must it be?

1 answer:

Blababa [14]3 years ago

6 0

<span>Option A, This type of quadrilaterals is a polygon and is called Rhombus because all sides are equal, each pair of acute and obtuse angles are opposite, their diagonals are distinct and perpendicular to each other, bisectors and have an inscribed circumference.</span>

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16^3x+8^x+6<br><br>Could you please give me the steps as well for this problem?

BARSIC [14]

Answer:

x = 2

Step-by-step explanation:

$16^{3x} = 8^{x+6} \\2^{4(3x)} = 2^{3(x+6)} -->$ (16 = $2^{4}$ and 8 = $2^{3}$ )

$2^{12x} = 2^{3x+18}$

Since the base number is 2, the exponents must equal each other.

So:

12x = 3x+18

9x = 18

x = 2

8 0

2 years ago

What is 11/15= 8/15-w

victus00 [196]

Answer: w= 1/5

Step-by-step explanation:

11/15=8/15 -w

-W= 8/15 -11/15

-w= 8-11/15 =-3/15

-w=-3/15

w=3/15= 1/5

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3 years ago

Tell whether the angles are adjacent or vertical. Then find the value of x.

soldier1979 [14.2K]

Adjacent : 53. Is the answer

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3 years ago

One vertex of a polygon is located at (3, –2). After a rotation, the vertex is located at (2, 3).

motikmotik

yes it is right when the vertex of the first polygon is located on 3 - 2 after rotation the work vertex will be there on (2 , 3) it is right

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2 years ago

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Semenov [28]

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2 years ago