This is a strange question, and f(x) may not even exist. Why do I say that? Well..
[1] We know that f(a+b) = f(a) + f(b). Therefore, f(0+0) = f(0) + f(0). In other words, f(0) = f(0) + f(0). Subtracting, we see, f(0) - f(0) = f(0) or 0 = f(0).
[2] So, what's the problem? We found the answer, f(0) = 0, right? Maybe, but the second rule says that f(x) is always positive. However, f(0) = 0 is not positive!
Since there is a contradiction, we must either conclude that the single value f(0) does not exist, or that the entire function f(x) does not exist.
To fix this, we could instead say that "f(x) is always nonnegative" and then we would be safe.
Answer:
$348
Step-by-step explanation:
40 + 8 = 48 x 7.25 = 348
Answer:
18-6y
Step-by-step explanation:
Answer:
Its A) y=3/2x
Step-by-step explanation:
-3/2x would be the exact opposite of 3/2x it would be the same line but facing the left side because its on the negative side. And the others are not the same as 3/2x.
Sorry if i could not explain that well, but I am 99% sure its A, y=3/2x
The couple would get 120,000
