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stiv31 [10]
3 years ago
5

Does the point (-2, 1) satisfy the inequality 6x + y > -11? YES OR NO

Mathematics
1 answer:
natali 33 [55]3 years ago
7 0

No, the given point does not satisfy the inequality

<em><u>Solution:</u></em>

Given inequality is 6x + y > -11

We have to find whether the point (-2, 1) satisfies the inequality

When we subsitute the given point into given inequality, values in both sides of inequality must satisfy the condition

Let us substitute the given point (x, y) = (-2, 1) in given inequality

6(-2) + 1 > -11

-12 + 1 > -11

-11 > -11 which is not true, Since -11 is equal to -11

So the given point does not satisfy the inequality

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Is y=3x-5 and 6x=2y+10 a solution
iVinArrow [24]
Y=3x-5
y-3x=-5
Times 2 from both side
y(2)-3x(2)=-5(2)
2y-6x=-10
Times negative from both side
(-)2y-6x(-)=(-)-10
-2y+6x=10
or
6x-2y=10


6x=2y+10
6x-2y=10
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3 years ago
Solve the system of equations.
MAXImum [283]

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D. (-2, -6) and (5,15)

Step-by-step explanation:

When you set the equations together, you get x^2-3x-10. You then set this equation equal to zero and get (x-5)(x+2) or x=-2 and x=5. Then, plug these x-values into each equation to get your y-values.

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2 years ago
Help me with this one
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9514 1404 393

Answer:

  "complete the square" to put in vertex form

Step-by-step explanation:

It may be helpful to consider the square of a binomial:

  (x +a)² = x² +2ax +a²

The expression x² +x +1 is in the standard form of the expression on the right above. Comparing the coefficients of x, we see ...

  2a = 1

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That means we can write ...

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But we need x² +x +1, so we need to add 3/4 to the binomial square in order to make the expressions equal:

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_____

Another way to consider this is ...

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  = (x +b/2)² +(c -(b/2)²)

for b=1, c=1, this becomes ...

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_____

* This process, "rewrite bx, add and subtract (b/2)²," is called "completing the square"—especially when written as (x-h)² +k, a parabola with vertex (h, k).

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3 years ago
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