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snow_lady [41]
4 years ago
8

Help me wit dis pleasee??

Mathematics
2 answers:
shutvik [7]4 years ago
7 0
X= 63 degrees. Every straight line segment with an angle will have 2 or more angles that all add up to 180 degrees, so you take 180 minus the angle measure (117) and you get 63. Y is a 90 degree angle, so you take 90 minus 63 and you have your answer of 27 degrees. 
X= 63
Y= 27
:)
valentina_108 [34]4 years ago
3 0
X is 63 and y is 27 thats the answer
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Find the measure of M
Neporo4naja [7]

Answer:

∠M = 78º

∠N = 68º

∠P = 34º

Step-by-step explanation:

we know that the inside of a triangle is equal to 180º. we also know that angle p and angle q equal 180º when added together because that's the angle of a straight line. first we need to find angle p.

180 - 146 = 34º

now we can set it up so that all the angles equal 180º when added together.

(5y + 3) + (4y + 8) + 34 = 180

5y + 4y = 9y

9y + 3 + 8 + 34 = 180

3 + 8 + 34 = 45

9y + 45 = 180

    -45      -45

-------------------

9y = 135

÷9      ÷9

y = 15

now we can plug 15 in for y

(5 x 15 + 3) = 78º

(4 x 15 + 8) = 68º

to double check, add all three angles and make sure they equal 180º

78 + 68 + 34 = 180

7 0
3 years ago
I need help please :(​
Anuta_ua [19.1K]
15x + 11x + 8x+5 = 180

34x + 5 = 180

34x = 180-5

34x = 175

x = 5.147


by substitution each value by of x by 5




75 + 55 + 45 = 175
5 0
3 years ago
Mischa wrote the quadratic equation 0=-x^2+4x-7 in standard form. If a = -1, what is the value of c in her equation?
gayaneshka [121]
The correct answer
C= -7
8 0
3 years ago
Consider the hyperbola represented by the equation: (picture)
forsale [732]

Answer:

- The center of hyperbola is (-2 , 3)

- The left vertex, if the hyperbola opens horizontally, or the

  bottom vertex, if it opens vertically, is (-6 , 3)

- The other vertex is (2 , 3)

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1, Where

- The length of the transverse axis is 2a

- The coordinates of the vertices are (h ± a , k)

- The length of the conjugate axis is 2b

- The coordinates of the co-vertices are (h , k ± b)

- The coordinates of the foci are (h ± c , k), where c² = a² + b²

* Now lets solve the problem

∵ (x + 2)²/4² - (y - 3)²/5² = 1

∵  (x - h)²/a² - (y - k)²/b² = 1

∴ a = 4 , b = 5

∴ h = -2 , k = 3

∵ The center of the hyperbola is (h , k)

∴ The center of hyperbola is (-2 , 3)

∵ The coordinates of the vertices are (h + a , k)  , (h - a , k)

∴ The coordinates of the vertices are (-2 + 4 , 3)  , (-2 - 4 , 3)

∴ The coordinates of the vertices are (2 , 3)  , (-6 , 3)

∴ The left vertex, if the hyperbola opens horizontally, or the

  bottom vertex, if it opens vertically, is (-6 , 3)

∴ The other vertex is (2 , 3)

6 0
4 years ago
Which ordered pair is in the solution set of y≥13x+4 ?
Zarrin [17]

Answer:

first one

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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