If you are looking to write an inequality equation that models this situation, then the answer would be: . The "at most" signals to use the less than or equal to sign.
Which ordered pair is in the solution set of y≥13x+4 ?
2 answers:
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Answer:
Option (2)
Step-by-step explanation:
Given expression is, y = (x + 3)² + (x + 4)²
By solving this expression,
y = x² + 6x + 9 + x² + 8x + 16
y = 2x² + 14x + 25
y = (2x² + 14x) + 25
y = 2(x² + 7x) + 25
y = 2[x² + 2(3.5x) + (3.5)² - (3.5)²] + 25
y = 2[x² + 2(3.5x) + (3.5)²] - 2(3.5)² + 25
y = 2(x + 3.5)² - 24.5 + 25
y = 2(x + 3.5)² + 0.5
Therefore, Option (2) will be the vertex form.
We can do this by the tree method. What I've done here is to divide each factor by prime numbers until we have only prime numbers left. For example the second level of the tree from the top has 350 and 2. This is because 750 = 2*350. the next level has 175 and 2 because 350 = 2*175.
At the end we are left with the prime factors and find that 700 = 7*5*5*2*2
At the end we are left with the prime factors and find that 700 = 7*5*5*2*2
Answer:
Step-by-step explanation:
p=,
(22+6)2-21=
44+12-21=
35=,
If you factor out the equation, you get that 35=4p(if you factor it out)
Therefore,