Solution
For this case we can use the following formula:
Where:
P= 400800 = present value
A= future value
r= 0.055 interest rate
n= 4, number of times that the interest is compund in a year (quarterly)
t= 4 years
Replacing we got:
then the interest would be:
b is correct! good job :)
Answer:
An interval that will likely include the proportion of students in the population of twelfth-graders who carry more than $15 is 960
Step-by-step explanation:
For example, Condition 1: n(.05)≤N
• The sample size (10) is less than 5% of the population (millions of musicians), so
the condition is met.
• Condition 2: np(1-p)≥10
• =
2
10
= .2
• 1 − = 10 .2 1 − .2 = 1.6 . This is less than 10 so this condition is not
met.
It would not be practical to construct the confidence interval.
Answer:
4y+5x is ur equation for your linear line
We should first calculate the average number of checks he wrote
per day. To do that, divide 169 by 365 (the number of days in a year) and you get (rounded) 0.463. This will be λ in our Poisson distribution. Our formula is
. We want to evaluate this formula for X≥1, so first we must evaluate our case at k=0.
To find P(X≥1), we find 1-P(X<1). Since the author cannot write a negative number of checks, this means we are finding 1-P(X=0). Therefore we have 1-0.3706=0.6294.
There is a 63% chance that the author will write a check on any given day in the year.<em />
