Problem 1
Answer: Closer to 1
Explanation:
There are 20 gumballs total. Half of this is 20/2 = 10 gumballs. If there's more than 10 of one color, then the probability of getting that color is closer to 1, than it is to 0. Here we have 12 pink which is greater than 10, so that's why the answer is closer to 1.
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Problem 2
Answer: Closer to 0
Explanation:
The amount of green (3) is less than 10, so that's why the probability is closer to 0 than it is to 1. We can see that 3/20 = 0.15 is less than 0.50
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Problem 3
Answer: Closer to 0
Explanation:
We have a similar situation compared to problem 2. This time we have 5/20 = 0.25 which is less than 0.50
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Problem 4
Answer: 48% chance; fairly likely
Explanation:
We have 12 green out of 25 total, so the probability of choosing green is 12/25 = 0.48 = 48%. While this probability is not over 50%, I still say it's fairly likely considering the other colors lead to smaller probabilities. For instance, purple has a chance of 6/25 = 0.24 = 24% and orange has a probability of 2/25 = 0.04 = 4%, both of which are smaller than 48%
Answer:
all is easy first do it in the bracketsand do it divied multiply add and substrate
Answer: A=351.68 cm²
Step-by-step explanation:
To find the area of the shaded region, we would subtract the area of the circle by the area of the inner circle.
Area of Circle



Area of inner (white) circle



Now that we have the area to the circle and inner circle, we would subtract to find the area of the shaded region.



Answer:
Hello :D
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
given that y varies directly with x then the equation relating them is
y = kx ← k is the constant of variation
to find k use the given condition y = 2 when x = 10
k =
=
= 
y =
x ← equation of variation
when x = 40, then
y =
× 40 = 8 → A