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2 years ago

Al mediodía en una ciudad se registra una temperatura de 13°C bajo

Mathematics

2 answers:

forsale [732]2 years ago

6 0

Answer:

-57

Step-by-step explanation:

+2($$?$!(-(&jeksljdjdkdnd

Dahasolnce [82]2 years ago

3 0

Answer

:La temperatura al final del día es de -57 grados centígrados.

espero que esto ayude

por cierto, espero que tengas un día increíble

Step-by-step explanation:

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Rebecca had 9/10 of a yard of ribbon. Then she gave 7/20 of a yard to a friend. How much does she have left? Explain your work

lianna [129]

9/10 - 7/20=(9x20) - (7x10)= 10x20= 110/200 110 divided by 10/ 200 divided by 10= 11/20. So that brings you to your answer of 11/20. hope this helps :)

4 0

3 years ago

Read 2 more answers

Consider a discrete random variable x with pmf px (1) = c 3 ; px (2) = c 6 ; px (5) = c 3 and 0 otherwise, where c is a positive

PtichkaEL [24]

Looks like the PMF is supposed to be

$\mathbb P(X=x)=\begin{cases}\dfrac c3&\text{for }x\in\{1,5\}\\\\\dfrac c6&\text{for }x=2\\\\0&\text{otherwise}\end{cases}$

which is kinda weird, but it's not entirely clear what you meant...

Anyway, assuming the PMF above, for this to be a valid PMF, we need the probabilities of all events to sum to 1:

$\displaystyle\sum_{x\in\{1,2,5\}}\mathbb P(X=x)=\dfrac c3+\dfrac c6+\dfrac c3=\dfrac{5c}6=1\implies c=\dfrac65$

Next,

$\mathbb P(X>2)=\mathbb P(X=5)=\dfrac c3=\dfrac25$

$\mathbb E(X)=\displaystyle\sum_{x\in\{1,2,5\}}x\,\mathbb P(X=x)=\dfrac c3+\dfrac{2c}6+\dfrac{5c}3=\dfrac{7c}3=\dfrac{14}5$

$\mathbb V(X)=\mathbb E\bigg((X-\mathbb E(X))^2\bigg)=\mathbb E(X^2)-\mathbb E(X)^2$
$\mathbb E(X^2)=\displaystyle\sum_{x\in\{1,2,5\}}x^2\,\mathbb P(X=x)=\dfrac c3+\dfrac{4c}6+\dfrac{25c}3=\dfrac{28c}3=\dfrac{56}5$
$\implies\mathbb V(X)=\dfrac{56}5-\left(\dfrac{14}5\right)^2=\dfrac{84}{25}$

If $Y=X^2+1$ , then $X^2=Y-1\implies X=\sqrt{Y-1}$ , where we take the positive root because we know $X$ can only take on positive values, namely 1, 2, and 5. Correspondingly, we know that $Y$ can take on the values $1^2+1=2$ , $2^2+1=5$ , and $5^2+1=26$ . At these values of $Y$ , we would have the same probability as we did for the respective value of $X$ . That is,

$\mathbb P(Y=y)=\begin{cases}\dfrac c3&\text{for }y=2\\\\\dfrac c6&\text{for }y=5\\\\\dfrac c3&\text{for }y=26\\\\0&\text{otherwise}\end{cases}$

Part (5) is incomplete, so I'll stop here.

8 0

3 years ago

How do you leave an answer in terms of pi?

Archy [21]

In terms of pi means to include pi in your answer. In other words, don't use 3.14 or 22/7 for pi.

8 0

2 years ago

Ray had 60 football cards last year.This year he has 200. Find the percent of change

bulgar [2K]

Answer:70%

Step-by-step explanation: no. of cards last year=60

no. of cards presently=200

increase in no. of cards=200-60

=140

%change=140/200 x 100

7 0

2 years ago

Beth works 8 2/4 hours, drives 1 1/4 hours, cooks 3/4 hours, and sleeps 7 2/4 hour's each day. How many hours of free time does

Jobisdone [24]

--------------------------------------------------------------------
Total time spent on work, drive cook and sleep
--------------------------------------------------------------------

$8 \frac{2}{4} + 1 \frac{1}{4} + \frac{3}{4} + 7 \frac{2}{4}$

$= 16 \frac{8}{4}$

$= 18$

------------------------------------------------------------------
Calculate Free Time
------------------------------------------------------------------
24 - 18 = 6

------------------------------------------------------------------
Answer: 6 hours of free time
------------------------------------------------------------------

5 0

3 years ago