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3 years ago

Kim drives 156 miles from rotherham to London.She has an average speed of 60 miles per hour.

1 answer:

5 0

Currently, you would ask "How long does it take to get from Rotherham to London?" You would do 156/60, which would be 2.6 hours. 2.6 hours is 156 minutes (2 hours, 36 minutes).
9:36 is when Kim would reach London, so yes.

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Please help me with these, find the missing side. Thank yu only if you know

abruzzese [7]

Answer:

7.48m (3s.f.)

Step-by-step explanation:

Let the missing side be x m.

Applying Pythagoras' Theorem,

x² +5²= 9²

x² +25= 81

x²= 81 -25 (-25 on both sides)

x²= 56

$x = \sqrt{56}$

$x = 2 \sqrt{14}$

x= 7.48 (3 s.f.)

∴ The missing side is 7.48 m (3s.f.)

8 0

3 years ago

-2 n is an integer what are the possible values of n

Neko [114]

Step-by-step explanation:

$n \in Z$

Where Z is set of integer.

3 0

3 years ago

Read 2 more answers

What is the range of the function f(x) = –2(6x) + 3?

padilas [110]

Answer: y=-12x+3 hope it helps

5 0

3 years ago

At the movie theatre, child admission is $5.10 and adult admission is $9.00 .

sveticcg [70]

Answer:

$5.10 X +9.00 Y = 831.60$

We also know that for Wedneday we have two times tickets for adults compared to child so we have

$Y =2x$

And using this condition we have:

$5.10 X + 18 X = 831.60$

And solving for X we got:

$X= \frac{831.60}{23.1}=36$

So then the number of tickets sold for child are 36

Step-by-step explanation:

For this problem we can set upt the following notation

X = number of tickets for child

Y= number of tickets for adults

And we know that the total revenue for Wednesday was 831.60. So then we can set up the following equation for the total revenue

$5.10 X +9.00 Y = 831.60$

We also know that for Wedneday we have two times tickets for adults compared to child so we have

$Y =2x$

And using this condition we have:

$5.10 X + 18 X = 831.60$

And solving for X we got:

$X= \frac{831.60}{23.1}=36$

So then the number of tickets sold for child are 36

8 0

3 years ago

Is a number of television in a household a discrete quantitative or continuous quantitative

mezya [45]

discrete, you cannot have 1.5 televisions

generally the number of X is a discrete variable.

continous = can contain decimal value (float values)

discrete = no decimal (integers)

7 0

3 years ago