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stellarik [79]
3 years ago
7

Phil has 19 other students in his math class. During class one day, the teacher asks for a volunteer to come up to the board. If

no one volunteered, one would be chosen randomly. If everyone was in the class that day, and the teacher did pick someone at random, what is the probability that the teacher will choose Phil.
Select one:

1/19

19/20

20/1

1/20
Mathematics
2 answers:
Stolb23 [73]3 years ago
7 0

Answer:

1/20

Step-by-step explanation:

if you do all kids there is 20. you have a 1 out of 20 people change so plz give brainest answer

Yuliya22 [10]3 years ago
3 0

Answer:

1/19

Since there are 19 students in the class, and this is a question of Phil.

Since there is only 1 Phil, it will be 1/19.

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If a student randomly guesses at 20 multiple-choice questions, find the probability that the student gets exactly four correct.
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Answer:

Probability = 0.190

Step-by-step explanation:

Given:

Number of questions, 'n' = 20

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Let event of choosing correct answer be success and its probability be represented by 'p'.

Therefore, event of choosing wrong answer is failure and its probability be represented by 'q'.

Now, probability of success is choosing one correct answer out of 4 options. So, p=\frac{1}{4}=0.25

Now, 'p' and 'q' are complements of each other. Therefore,

q=1-p=1-0.25=0.75

Now, we need 4 successes. Therefore, x=4

Using Bernoulli's theorem to find 'x' successes from 'n' questions, we get:

P(x)=_{x}^{n}\textrm{C}p^xq^{n-x}

Plug in 4 for 'x', 20 for 'n', 0.25 for 'p' and 0.75 for 'q'. Solve.

P(4)=_{4}^{20}\textrm{C}(0.25)^4(0.75)^{20-4}\\P(4)=_{4}^{20}\textrm{C}(0.25)^4(0.75)^{16}\\P(4)=4845\times (0.25)^4\times (0.65)^{16}\\\\P(4)=0.1896\approx0.190

Therefore, the probability of getting 4 correct answers out of 20 questions is 0.190.

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