<u>Solution-</u>
As the question is not complete so contemplating all the possible scenarios,
1st - z² + 10z + 25
2nd - z² - 10z + 25
For,
![z^2 + 10z + 25 = (z)^2+2.z.5+(5)^2 = (z+5)^2=(z+5)(z+5)](https://tex.z-dn.net/?f=z%5E2%20%2B%2010z%20%2B%2025%20%3D%20%28z%29%5E2%2B2.z.5%2B%285%29%5E2%20%3D%20%28z%2B5%29%5E2%3D%28z%2B5%29%28z%2B5%29)
And for,
![z^2 - 10z + 25 = (z)^2-2.z.5+(5)^2 = (z-5)^2=(z-5)(z-5)](https://tex.z-dn.net/?f=z%5E2%20-%2010z%20%2B%2025%20%3D%20%28z%29%5E2-2.z.5%2B%285%29%5E2%20%3D%20%28z-5%29%5E2%3D%28z-5%29%28z-5%29)
So, the factored form of the polynomials are,
![(z+5)(z+5) \ and \ (z-5)(z-5)](https://tex.z-dn.net/?f=%28z%2B5%29%28z%2B5%29%20%5C%20and%20%5C%20%28z-5%29%28z-5%29)
Let's assume
x is number of hours worked
y is amount paid
Since, this is linear relationship
We can select any two points
(2,36.50) and (4,73)
so, we can also write as
x1=2 , y1 =36.50
x2=4 , y2=73
Firstly, we can find slope
![m=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
we can plug values
![m=\frac{73-36.50}{4-2}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B73-36.50%7D%7B4-2%7D)
![m=18.25](https://tex.z-dn.net/?f=m%3D18.25)
now, we can use point slope form of line
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
we can plug values
![y-36.50=18.25(x-2)](https://tex.z-dn.net/?f=y-36.50%3D18.25%28x-2%29)
now, we can solve for y
![y=18.25x](https://tex.z-dn.net/?f=y%3D18.25x)
or
..............Answer
The answer would be d or the last one
Answer:
∠ 1 = 102°
Step-by-step explanation:
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ 1 is an exterior angle of the triangle , then
∠ 1 = 33° + 69° = 102°
bisect = to cut into two equal halves.
so from that theorem Juan used we can derive that once both diagonals bisect each other, the halves of AO = OC and DO = OB.