A polygon has coordinates A(-7, 8), B(-4, 6), C(-4, 3), D(-8, 3), and E(-9, 6). What are the coordinates of its image, polygon A
Burka [1]
The correct answer is third set of points: <span>A′(6, 10), B′(4, 7), C′(1, 7), D′(1, 11), E′(4, 12)
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We can figure out this answer, just by looking at the first point A. If we rotate it 270 degree counterclockwise, if will go from the second quadrant to the first quadrant.
The new point will be (8, 7). If we move left 2 and up 3, we will be at the point (6, 10). Only the second choice matches this.</span>
Step-by-step explanation:
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The slope of first line is m 1= ( 1 - 0 ) / ( - 2 - ( - 6 ) );
m = 1 / 4 ;
Because the second line is perpendicular to the first line, m2 * m1 = - 1 ;
m2 * ( 1 / 4 ) = -1;
m2 = - 4 ;
The equation of the second line is : y - 3 = ( - 4 )( x - 2 );
y - 3 = -4x + 8 ;
y = -4x + 11.
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2=log(3x+4)
y = loga b a^y = b
since this is base 10
10^2 =3x+4
100 = 3x+4
subtract 4 from each side
96 =3x
divide by 3
32=x
