An arithmetic sequence has a common difference.
143 - 130 = 13
156 - 143 = 13
169 - 156 = 13
The common difference is 13.
a1 = 130
a2 = 130 + 13
a3 = 130 + 2 * 13
a4 = 130 + 3 * 13
...
an = 130 + (n - 1) * 13
an = 130 + 13(n - 1)
an = 130 + 13n - 13
an = 117 + 13n
an = 13n + 117
Answer:
When you have an imaginary number in the denominator multiply the numerator and the denominator by the conjugate of the denominator.
Answer:
-6 and -3 for the dots
Step-by-step explanation:
hope this is correct im bad at math
1: square root of 2
2: cube root of 2, squared
3: square root of 3, squared
4: cube root of 3
hopefully this helps you :)
