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prohojiy [21]
3 years ago
8

WILL GIVE BRAINLIEST: if the roots of the equation x^3 +px^2+qx+r = 0 are 2, 3, and 4, find the values of p, q, and r.

Mathematics
1 answer:
klasskru [66]3 years ago
5 0
8+4p+2q+r=0
27+9p+3q+r=0
64+16p+4q+r=0
P=-9
Q=26
R=-24
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A stone is launched into the air from a height of 240 feet. The height, h, of the stone, in feet, t seconds after launch is give
rosijanka [135]

A projectile is an object <u>launched</u> into space, and moving under the <em>influence</em> of <u>gravity</u> and <u>momentum</u>. The <em>stone</em> here is an example. Thus, the <em>time</em> taken for the stone to reach the ground is 10 seconds.

On <em>launching</em> of the stone into <u>space</u>, it behaves as a <u>projectile</u>. Thus moving under the <em>influence</em> of gravity and its momentum. Its <u>momentum</u> is the <em>product</em> of its <u>mass </u>and <u>velocity</u>.

The height h, is given as:

h = 16t^{2} + 32t + 240

Differentiating the expression with respect to t, we have;

32t + 32 = 0

t = -1 seconds

Substitute the value of time, t, in the equation for the height;

h = 16 - 32 + 240

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h = 224 m

Total height, S = 240 + 224

                         = 464

S = 464 m

The total height covered by the stone is 464 m.

From the second equation of <em>free fall</em>,

S = Ut + \frac{1}{2}gt^{2}

S = \frac{1}{2}gt^{2}

464 = \frac{1}{2}*9.8*t^{2}

t^{2} = \frac{928}{9.8}

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t = \sqrt{94.694}

 = 9.7311

t ≅ 10 seconds

The <em>time taken</em> for the stone to hit the ground is 10 seconds.

Thus option A is the required answer.

Visit: brainly.com/question/13834669

7 0
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