WILL GIVE BRAINLIEST: if the roots of the equation x^3 +px^2+qx+r = 0 are 2, 3, and 4, find the values of p, q, and r.
1 answer:
You might be interested in
Answer:
The roots are -5, 1.
Step-by-step explanation:
The roots of a function are also the Ox intercepts, so basically we're finding when is the function equal to '0'.
Answer:
<h2> RS = 47</h2>Step-by-step explanation:
RV=VU and SW=WT ⇒
Therefore:
3x + 5 = 4x - 11 {subtract 5 from both sides)
3x = 4x - 16 {subtract 4x from both sides)
-x = -16 {divide both sides by (-1)}
x=16
So:
RS = 2x + 15 = 2×16 + 15 = 32 + 15 = 47