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2 years ago

Find x, find jl . any help is deeply appreciated :) !

Mathematics

1 answer:

Doss [256]2 years ago

4 0

Answer:

6. x = 15

7. JL = 78

Step-by-step explanation:

6. 8x - 23 = ½(10x + 44) (midsegment theorem)

Multiply both sides by 2

2(8x - 23) = 10x + 44

16x - 46 = 10x + 44

Collect like terms

16x - 10x = 46 + 44

6x = 90

Divide both sides by 6

x = 90/6

x = 15

7. MN = 5x - 16

JL = 4x + 34

MN = ½(JL) (midsegment theorem)

5x - 16 = ½(4x + 34) (substitution)

2(5x - 16) = 4x + 34

10x - 32 = 4x + 34

Collect like terms

10x - 4x = 32 + 34

6x = 66

x = 66/6

x = 11

JL = 4x + 34

Plug in the value of x

JL = 4(11) + 34 = 44 + 34

JL = 78

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Read 2 more answers

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Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

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1 year ago

Find x, find jl . any help is deeply appreciated :) !​

Find x, find jl . any help is deeply appreciated :) !