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Paha777 [63]
3 years ago
11

Solve for the missing angles / show your work! Help pls!

Mathematics
1 answer:
Alenkasestr [34]3 years ago
3 0

Answer:

sum=(n-2)*180

sum=(4-2)*180

sum=2*180

sum=360º

if T=K, T=100º

360-(100+100+20)=E

E=360-220

E=140º

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vampirchik [111]

Answer:The number is -1.5

Step-by-step explanation:

The answer is -1.5 because if you can't use a number less than -1.5 or greater than -1.5 than the answer should be -1.5.

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0.62 as a percent <br> (STEP BY STEP)
jolli1 [7]

Answer:

0.62 = 0.62 × 100/100 = (0.62 × 100)/100 = 62/100 = 62%;

In other words:

1) Multiply that number by 100.

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Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard devia
lesya692 [45]

Answer: P(x > - 0.23) = 0.41

Step-by-step explanation:

Since we are assuming that the readings at freezing on a batch of thermometers are normally distributed, we would apply the formula for normal distribution which is expressed as

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Where

x = the readings at freezing on a batch of thermometers.

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σ = standard deviation

From the information given,

µ = 0°C

σ = 1.00°C

the probability of obtaining a reading less than -0.23°C is expressed as

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7 0
3 years ago
What is x ? 4x+8y =64
White raven [17]
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7 0
4 years ago
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valentinak56 [21]

Answer:

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This is a compound decay problem. Which has the formula:

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F is the future amount (we want it to be 2000)

P is the present amount (which is 4600)

r is the rate of decay, depreciation (20% per year means 20/100 = 0.2)

t is the time in years (which we want to find)

Substituting, we find:

F=P(1-r)^t\\2000=4600(1-0.2)^t\\2000=4600(0.8)^t\\0.4348=0.8^t

Now we take natural log (Ln) of both sides and solve:

Ln(0.4348)=Ln(0.8^t)\\Ln(0.4348)=tLn(0.8)\\t=\frac{Ln(0.4348)}{Ln(0.8)}\\t=3.73

So, it will take about 3.73 years for the value to depreciate to $2000

3 0
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