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aleksandrvk [35]
3 years ago
8

The graph shows the charges of an instructor. The instructor charges an initial fee and then an hourly rate of $8.00 an hour for

private lessons. Determine the instructor’s initial charge from the graph.
Mathematics
2 answers:
tresset_1 [31]3 years ago
5 0

Answer: $20.00

Step-by-step explanation: On Edgenuity!!!!!

Butoxors [25]3 years ago
4 0

Answer:

$20.00

Step-by-step explanation:

I took a test and got it correct.

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I keep getting (10,5) or (0,5) someone pls help
rodikova [14]

Answer:

(4,-3)

Step-by-step explanation:

Multiplying the bottom equation by -6, we get -6x+12y=-60.

Adding this to the first equation gives 15y=-45, and thus y=-3.

So, it follows that 6x+3(-3)=15, and thus x=4.

4 0
2 years ago
2+6i/2-4i = a + bi What is the value of a? What is the value of b?
Talja [164]

\dfrac{2+6i}{2-4i}\\\\\\=\dfrac{2(1+3i)}{2(1-2i)}\\\\\\=\dfrac{1+3i}{1-2i}\\\\\\=\dfrac{(1+3i)(1+2i)}{(1-2i)(1+2i)}\\\\\\=\dfrac{1+2i+3i+6i^2}{1-(2i)^2}\\\\\\=\dfrac{1+5i-6}{1+4}~~~~;[i^2=-1]\\\\\\=\dfrac{5i-5}{5}\\\\\\=\dfrac{5(i-1)}5\\\\=i-1\\\\=-1+i\\\\\text{It is in a form of a +bi so,}~ a = -1~ \text{and}~ b = 1

6 0
3 years ago
Problem: a circle is inscribed in a square. The squares perimeter is 16 times the square root of 6. What is the probability of s
Oksi-84 [34.3K]
I got 21% at selecting a point outside.
Explanation: Since the perimeter is 16sqrt (6), each side must be 4sqrt (6)
This also means that the diameter is 4sqrt (6).

To find the area of a circle, we need to find the radius (2sqrt (6)).
Area of circle is pi × (2sqrt (6))^2 = 24pi or approximately 75.4 units^2
Area of square is 4sqrt (6)^2 = 96

Thus, let's take the area of the circle and subtract that from the area of our square to yield approx. 20.6 units^2
and now divide through by 96 to yield 21%
8 0
3 years ago
Find the term indecent of x in the expansion of (x^2-1/x)^6
Mars2501 [29]

By the binomial theorem,

\displaystyle \left(x^2-\frac1x\right)^6 = \sum_{k=0}^6 \binom 6k (x^2)^{6-k} \left(-\frac1x\right)^k = \sum_{k=0}^6 \binom 6k (-1)^k x^{12-3k}

I assume you meant to say "independent", not "indecent", meaning we're looking for the constant term in the expansion. This happens for k such that

12 - 3k = 0   ===>   3k = 12   ===>   k = 4

which corresponds to the constant coefficient

\dbinom 64 (-1)^4 = \dfrac{6!}{4!(6-4)!} = \boxed{15}

3 0
3 years ago
Show all of your work. Simplify the expression: - 3a + 7 + 5a​
Eva8 [605]

Answer:

2a + 7

Step-by-step explanation:

-3a + 7 +5a

<em>subtract the negative 3 from the 5</em>

2a + 7

4 0
3 years ago
Read 2 more answers
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