Option B:
The perimeter of ΔABC is 28 units.
Solution:
AD = 5, DC = 6 and AB = 8
AD and AE are tangents to a circle from an external point A.
BE and BF are tangents to a circle from an external point B.
CD and CF are tangents to a circle from an external point C.
<em>Tangents drawn from an external point to a circle are equal in length.</em>
⇒ AD = AE, BE = BF and CD = CF
AE = 5
AE + BE = AB
5 + BE = 8
Subtract 5 from both sides.
BE = 3
BE = BF
⇒ BF = 3
CD = CF
⇒ CF = 6
Perimeter of the polygon = AE + BE + BF + CF + CD + AD
= 5 + 3 + 3 + 6 + 6 + 5
= 28
The perimeter of ΔABC is 28 units.
Option B is the correct answer.
Answer:
Solution in photo
Step-by-step explanation:
Answer:
Step-by-step explanation:
For A you can use angles in a triangle adding to 180 degrees.
For a you can use the sine rule.
From there you can use Pythagoras to work out c.
Hope this helps :)
Answer:
This construction shows how to draw the perpendicular bisector of a given line segment with compass and straightedge or ruler. This both bisects the segment (divides it into two equal parts, and is perpendicular to it. It finds the midpoint of the given line segment.
Answer:
X=6
Y= - 1
Step-by-step explanation:
X-y =7
X+y =5 cross - y and y
_______
X+x =7 +5
2x= 12
X= 12/2
X= 6
Replace X in first equation:
X - y =7
6 - y =7
6 - 7 =y
y = - 1
Hope this helps you.. Good Luck!
