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Allushta [10]
3 years ago
15

What is the image of N for a 300° counterclockwise rotation about the center of the regular hexagon? Will give brainiest only if

answered correctly with explanation

Mathematics
1 answer:
OLEGan [10]3 years ago
6 0

Answer:

H

Step-by-step explanation:

here, the question says that the given regular hexagon needs to be rotated counter clockwise 300°, considering the edges labels, each movement from one edge to other is 60° as 360/6 =60.

focus on N and move on anti clockwise.

When N rotates anti clockwise about center from original to position G, is 60°,

when N moves on anti clockwise about center from original to position A is 120°.

similarly, to X is 180°, to E is 240° and to H is 300°.

so, the new position of N when rotated anti clockwise about origin of the hexagon will be at H.

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we know that

<u>in the triangle PQR</u>

m∠PQR+m∠QPR+m∠QRP=180°------> the sum of the internal angles of a triangle is equal to 180 degrees

(m∠PQR+m∠QRP)+74°=180°-------> (m∠PQR+m∠QRP)=106°

we know that

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