Answer:
<u>A. p(hat) = .139</u>
We divide our sample population by the amount who tested positive. 14851/107109 = .139.
<u>B. 1.62 million</u>
We just multiply the p times the population. 11.69 M * .139 = 1.62 M
<u>C. No</u>
It depends upon the sample method. From what I can tell, I assume all conditions are met and it was not biased.
If it wasn't random, that is a problem, but we aren't given this information.
We can test if it's small enough. It can't be larger than 10% of the population. 107109 * 10 < 11.69 million, so it's small enough.
We can also test if it's large enough. np and nq must be greater than 10. 107100 * .139 > 10, 107100 * .861 > 10.
Answer:
there are 15 birds all together and 5 black birds on the tree.
Step-by-step explanation:
It will take 12 truckloads to fill up one warehouse. Hope this helps.
Answer:
![\theta=270^\circ](https://tex.z-dn.net/?f=%5Ctheta%3D270%5E%5Ccirc)
Step-by-step explanation:
<u>Given Equation and Parameters</u>
![sin^2\theta-4sin\theta-5=0,\: 0^\circ\leq\theta\leq 360^\circ](https://tex.z-dn.net/?f=sin%5E2%5Ctheta-4sin%5Ctheta-5%3D0%2C%5C%3A%200%5E%5Ccirc%5Cleq%5Ctheta%5Cleq%20360%5E%5Ccirc)
<u />
<u>Calculation</u>
Let
, thus:
![u^2-4u-5=0\\\\(u+1)(u-5)=0\\\\u=-1,\: u=5](https://tex.z-dn.net/?f=u%5E2-4u-5%3D0%5C%5C%5C%5C%28u%2B1%29%28u-5%29%3D0%5C%5C%5C%5Cu%3D-1%2C%5C%3A%20u%3D5)
![sin\theta=-1\\\\\theta=270^\circ](https://tex.z-dn.net/?f=sin%5Ctheta%3D-1%5C%5C%5C%5C%5Ctheta%3D270%5E%5Ccirc)
![sin\theta=5\\\\\theta=unde fined](https://tex.z-dn.net/?f=sin%5Ctheta%3D5%5C%5C%5C%5C%5Ctheta%3Dunde%20fined)
<u>Conclusion</u>
![\theta=270^\circ](https://tex.z-dn.net/?f=%5Ctheta%3D270%5E%5Ccirc)
Answer:
![-16.2](https://tex.z-dn.net/?f=-16.2)
Step-by-step explanation:
![-9.2+(-7)=-16.2](https://tex.z-dn.net/?f=-9.2%2B%28-7%29%3D-16.2)