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SVEN [57.7K]
4 years ago
7

Ron wrote the pattern shown below. What is the rule for following Ron's pattern? 11, 36, 86, 186

Mathematics
1 answer:
dsp734 years ago
5 0
Add on the next multiple of 25 each time. Not sure if you need the equation but I think its
n = 25n - 14
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Help me out? tysvm!!!
Sophie [7]

Answer: 103

Step-by-step explanation:

8 x 6.5 = 52,

52 + 8 = 60 (pints in total)

there are 2 cups in 1 pint so 60 x 2 = 120

120 - 17 = 103

3 0
3 years ago
PLEASE HELP!! ASAP! WILL GIVE BRAINLIEST!
mihalych1998 [28]
I think it is c I hope this help you
7 0
3 years ago
SOMEONE PLS HELP ASAP!!!
ladessa [460]

Answer: h(x)=10(0.4)^x

Step-by-step explanation:

The exponential function h, represented in the table, can be written as h(x)=ab^x

From table, at x=0, h(x) =10

Put theses values in equation,, we get

10=a.b^0\\\\\Rightarrow\ 10=  a (1)\\\\\Rightarrow\ a= 10

Also, for x= 1 , h(x) = 4, so put these values and a=10 in the equation , we get

4=10b^1\\\\\Rightarrow\ b=\dfrac{4}{10}\\\\\Rightarrow\ b= 0.4

Put value of a and b in the equation ,

h(x)=10(0.4)^x  →  Required equation.

5 0
3 years ago
Change the subject of the equation v = u + at to a.
emmasim [6.3K]
<h3>Answer ↓</h3>

<h3>Calculations ↓</h3>

In order to make a the subject of this equation , we need to get a by itself .

The current equation is :

v = u + at

Subtract u on both sides :

v-u=at

Now, divide by t on both sides :

v-u/t=a

<h3>So the formula looks like ↓</h3>

\boxed{\\\begin{minipage}{3cm}Equation \\ a=$\displaystyle\frac{v-u}{t} $ \\ \end{minipage}}

hope helpful ~

8 0
3 years ago
How do you express sin x + cos x in terms of sine only?
frez [133]

Answer:

\sin x + \sqrt{1-\sin^2x}

Step-by-step explanation:

Given: sin x + cos x

To change the given trigonometry expression in term of sine only.

Trigonometry identity:-

  • \sin^2x+\cos^2x=1
  • \cos x=\sqrt{1-\sin^2x}

Expression: \sin x+\cos x

We get rid of cos x from expression and write as sine form.

Expression: \sin x + \sqrt{1-\sin^2x}        \because \cos x=\sqrt{1-\sin^2x}

Hence, The final expression is only sine function.

4 0
4 years ago
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