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3 years ago

What is the difference between rate and unit rate

Mathematics

1 answer:

dalvyx [7]3 years ago

4 0

Unit rate is in the quantity of one.
2/1 is a unit rate
6/3 is a rate
4/1 is a unit rate

You might be interested in

1. Simplify the expression: 4+36+(10-8)’-3+7 A. 130 B. 100 C. 38 D. 37

Alika [10]

Answer:

The answer isn't in the options anyway I'll write it. the answer is 46.

Step-by-step explanation:

According to BODMAS rule - addition should be done first so

4+36= 40 and -3 +7 = 4 so 40+4 ,= 44

then we should do subtracting so, 10-8 = 2

to conclude we should bring the equation to an end so,

44+2 = 46

HOPE THIS HELPS YOU

6 0

2 years ago

Outside temperature over a day can be modelled as a sinusoidal function. Suppose you know the high temperature for the day is 10

WINSTONCH [101]

Answer:

The function for the outside temperature is represented by $T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right]$ , where t is measured in hours.

Step-by-step explanation:

Since outside temperature can be modelled as a sinusoidal function, the period is of 24 hours and amplitude of temperature and average temperature are, respectively:

Amplitude

$A = \frac{100\º-70\º}{2}$

$A = 15\º$

Mean temperature

$\bar T = \frac{70\º+100\º}{2}$

$\bar T = 85\º$

Given that average temperature occurs six hours after the lowest temperature is registered. The temperature function is expressed as:

$T(t) = \bar T + A \cdot \sin \left[2\pi\cdot\frac{t-6\,h}{\tau} \right]$

Where:

$\bar T$ - Mean temperature, measured in degrees.

$A$ - Amplitude, measured in degrees.

$\tau$ - Daily period, measured in hours.

$t$ - Time, measured in hours. (where t = 0 corresponds with 5 AM).

If $\bar T = 85\º$ , $A = 15\º$ and $\tau = 24\,h$ , the resulting function for the outside temperature is:

$T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right]$

3 0

2 years ago

1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

2 years ago

Adam has an inflatable pool toy

dalvyx [7]

Answer:

yes

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

I need help on the Math question?

mrs_skeptik [129]

Answer:

The answer is D.

Step-by-step explanation:

3x*3x = 9x^2

3x*2= 6x

5*3x=15x

5*2=10

6x+15x=21x

9x^2+21x+10

3 0

2 years ago