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3 years ago

11

Mathematics

1 answer:

emmainna [20.7K]3 years ago

3 0

I think it is B because 11 is just 11 so yeah

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On a particular road map 1/2 inch represents 18 miles about how many miles apart are 2 towns that are 21/2 inches apart on this

andrew-mc [135]

So if 1/2 = 18 miles, we want to first find how many sets of 1/2 are in 21/2. We can just do this by dividing.

(21/2) / (1/2) = 21

So we know that there are 21 sets of 1/2 in 21/2, and since 1/2 and 18 are equal, we can say we know there are 21 sets of 18.

We can multiply to find this.

21 * 18 = 378

So two towns are 378 miles apart.

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2 years ago

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What’s 44/24 As a mixed number

Zina [86]

Answer:

1 5/6

Step-by-step explanation:

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2 years ago

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A video game randomly chooses your car color and type. The probability of getting a red car is 0.25, and the probability of gett

EleoNora [17]

In probability 2 events are independent if the occurrence of 1 event does not affect the occurrence of the other event. Mathematically, if event A and event B are independent, then $P(A\&B)=P(A)\times P(B)$ . For our two events in this problem we have that $P(A)=0.25$ and $P(B)=0.40$ . If these two events are independent, then we should have that,

$P(A\&B)=P(A)\times P(B)\\P(A\times B)=0.25\times 0.4=0.1.$

.A and B are independent events if the probability of A and B is 0.1

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2 years ago

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Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

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2 years ago

The polygon Q(3, 2), R(6,5), S(6, 2)

ycow [4]

Answer:

Q' (12,8) , R'( 24,20) and S' (24,8)

Step-by-step explanation:

Here, we want to get the coordinates of the image after dilating the pre-image by a scale factor of 4

What we have to do here is to multiply each of the coordinate on the pre-image by 4

We have this as;

Q' = (4*3, 2 * 4) = (12,8)

R' = (4*6, 4*5) = (24,20)

s' = (4*6, 4*2) = (24,8)

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2 years ago