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3 years ago

The element chlorine (Cl) has 17 protons and 17 electrons. What happens to an atom of chlorine (Cl) if it gains an electron?

Chemistry

2 answers:

Greeley [361]3 years ago

5 0

Explanation:

when an atom gain an electron the components of the electron will change as:

1 proton- 18

2. electron- 18

3. Atomic number - 18

4. mass number- 36

Vesna [10]3 years ago

4 0

Answer:

It becomes negatively charged

Explanation:

An atom of chlorine having equal number of protons and electrons is neutral. The protons are the positively charged particles located in the nucleus of an atom. Electrons are negatively charged particles located outside the nucleus.

When the number of electrons and protons are the same, such an atom is neutral.

If the number of protons is more, the atom becomes positively charged.

In this case, the atom adds or gains an electron making the number of electrons to go from 17 to 18. This is more than the number of protons which are 17 by 1. The charge on the atom is therefore -1.

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What's the electron configuration of an N⁻³ ion

tatuchka [14]

The electronic configuration of n - 3 ion is [He] 2s2 2p3.

5 0

2 years ago

Draw a diagram using H+ signs and OH- symbols of a solution that is acidic. Hint: Use the

Dimas [21]

More positive ions shows acidic whereas more negative ions indicates basic solution.

<h3>Which charge show acidic solution?</h3>

That side which has more positive charges is considered as acidic solution while on the other hand, that region where negative charges are present in large number as compared to positive charges is considered as basic or alkaline solution.

So we can conclude that more positive ions shows acidic whereas more negative ions indicates basic solution.

Learn more about charge here: brainly.com/question/25923373

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4 0

2 years ago

Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluor

jenyasd209 [6]

Answer:

27.9 g

Explanation:

CsF + XeF₆ → CsXeF₇

First we convert 73.1 g of cesium xenon heptafluoride (CsXeF₇) into moles, using its molar mass:

Molar mass of CsXeF₇ = 397.193 g/mol

73.1 g CsXeF₇ ÷ 397.193 g/mol = 0.184 mol CsXeF₇

As 1 mol of cesium fluoride (CsF) produces 1 mol of CsXeF₇, in order to produce 0.184 moles of CsXeF₇ we would need 0.184 moles of CsF.

Now we convert 0.184 moles of CsF to moles, using the molar mass of CsF:

Molar mass of CsF = 151.9 g/mol

0.184 mol * 151.9 g/mol = 27.9 g

4 0

3 years ago

When an aqueous solution of KBr is electrolyzed,

zhenek [66]

KBr + H2O = KOH + Br2 + H2

So we know that we need a 2 on the left of kbr so it would equal the right Br.

=2KBr
now put a 2 in front of KOH since we need a 2k on right side

Now we put a 2 infront of H2O which wil make 4 h's and 2 o's

2h2o

now it is balanced

2KBr + 2H2O = 2KOH + Br2 + H2

3 0

4 years ago

El hipoclorito de sodio (NaClO), es vendido en una solución clara de ligero color verde-amarillento y un olor característico que

vivado [14]

Respuesta:

16,7 mL

Explicación:

Paso 1: Información provista

Concentración inicial (C₁): 6%

Volumen inicial (V₁): ?

Concentración final (C₂): 0,5%

Volumen final (V₂): 200 mL

Paso 2: Calcular el volumen de la solución concentrada

Queremos preparar una solución diluida de hipoclorito de sodio a partir de una concentrada. Podemos calcular el volumen inicial que debemos tomar usando la regla de dilución.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0,5% × 200 mL / 6% = 16,7 mL

6 0

3 years ago