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2 years ago

What is the name of NaC2H3O2?

Chemistry

2 answers:

enot [183]2 years ago

7 0

Answer: The answer is Sodium acetate.

Explanation: Hope this helps plz mark brainliest.

Elena-2011 [213]2 years ago

6 0

Sodium Acetate, hope it helps

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Melissa's mother was making chocolate chip cookies, but told Melissa that she shouldn't eat the raw cookie dough. Why is it unsa

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3 years ago

How does a volcano erupt ?

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3 years ago

If the pH of vinegar is 3.0, what is the concentration of H+ in vinegar?

Cerrena [4.2K]

Answer: The concentration of $H^{+}$ ions in vinegar is 0.001 M.

Explanation:

Given: pH = 3.0

pH is the negative logarithm of concentration of hydrogen ion.

The expression for pH is as follows.

$pH = - log [H^{+}]$

Substitute the value into above expression as follows.

$pH = - log [H^{+}]\\3.0 = - log [H^{+}]\\conc. of H^{+} = antilog (- 3.0)\\= 0.001 M$

Thus, we can conclude that the concentration of $H^{+}$ ions in vinegar is 0.001 M.

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2 years ago

Clouds form when water vapor _____ to form small droplets. A. humidifies B. condenses C. evaporates D. precipitates

PtichkaEL [24]

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4 0

3 years ago

Read 2 more answers

A synthesis reaction takes place when carbon monoxide (CO) and hydrogen gas (H2) react to form methanol (CH3OH). How many grams

jek_recluse [69]

The mass of methanol produced is 8.0 g.

We have the masses of two reactants, so this is a limiting reactant problem.

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.

Step 1. Gather all the information in one place with molar masses above the formulas and everything else below them.

MM: ___28.01 2.016 ___32.04

_______CO + 2H_2 → CH_3OH

Mass/g: 7.0 __2.5

Step 2. Calculate the moles of each reactant

Moles of CO = 7.0 g CO × (1 mol CO/28.01g CO) = 0.250 mol CO

Moles of H_2 =2.5 g H_2 × (1 mol H_2/2.016 g H_2) = 1.24 mol H_2

Step 3. Identify the limiting reactant

Calculate the moles of CH_3OH we can obtain from each reactant.

From CO: Moles of CH_3OH = 0.250 mol CO × (1 mol CH_3OH /1 mol CO)

= 0.250 mol CH_3OH

From H_2: Moles of CH_3OH = 1.24 mol H_2 × (1 mol CH_3OH /2 mol H_2)

= 0.620 mol CH_3OH

CO is the limiting reactant because it gives the smaller amount of CH_3OH.

Step 4. Calculate the mass of CH_3OH

Mass of CH_3OH = 0.250 mol CH_3OH × (32.04 g CH_3OH /1 mol CH_3OH) = 8.0 g CH_3OH

3 0

3 years ago