Answer:
Ba(OH)2 + 2 HCl → BaCl2 + 2 H2O
The reactants are present in equimolar amounts, so there is no excess or limiting reactants.
(0.0500 L) x (0.600 mol/L HCl) x (2 mol H2O / 2 mol HCl) = 0.0300 mol H2O
(4.184 J/g·°C) x (50.0 g + 50.0 g) x (25.82 - 21.73)°C = 1711.256 J
(1711.256 J) / (0.0300 mol H2O) = 57042 J/mol = 57.0 kJ/mol H2O
Explanation:
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Answer:
5.66g/ml
Explanation:
Mass of Metal Slug, m = 25.17g
Volume of container (flask), v = 59.7ml
Mass of Methanol, M = 43.7g with density, d = 0.791g/ml
Therefore,
Volume of Methanol = M/d = 43.7 / 0.791 = 55.25ml
Volume of Metal slug in the flask = v - V = 59.7 - 55.25 = 4.45ml
Density of Metal slug = mass of metal slug / volume of metal slug
= 25.17 / 4.45 = 5.66g/ml
Explanation:
this equation is balanced
if you look at it carefully
k=1
f=1
o=2
we do not have any opposing element
Answer:
c. 0.750 atm
.
Explanation:
Hello!
In this case, since the two vessels have different volume, we can see that the gas is initially at 3.00 atm into the 1.00-L vessel, but next, it is allowed to move towards the 3.00-L vessel, meaning that the final volume wherein the gas is located, is 4.00 L; therefore, we use the Boyle's law to compute the final pressure:
Therefore the answer is c. 0.750 atm
.
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