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4 years ago

How does the reaction, A + BC ⇌ AB + C, differ from the reaction, N2 + 3H2 ⇌ 2NH3 + energy, by which ammonia is synthesized?

Chemistry

2 answers:

Rzqust [24]4 years ago

8 0

Answer:

A is a single displacement reaction; B is a combination (synthesis) reaction.

Explanation:

The first reaction

A + BC → AB + C

This is a single displacement reaction, in which an element A displaces another element C from its compound BC.

The second reaction

N2 + 3H2 → 2NH3

The coefficients don't matter in determining the type of reaction, so we can rewrite this equation as

A + B → AB

It then becomes more obvious that this is a combination (synthesis) reaction, in which two elements combine to form a compound.

-BARSIC- [3]4 years ago

6 0

Answer:

N₂+3H₂ ⇄2NH₃ is a thermochemical reaction whereas A+BC⇄AB is not.

A+BC⇄AB is a reaction of pure a element with a compound while N₂+3H₂ ⇄2NH₃ is a reaction between two pure elements.

Explanation:

Let A+BC⇄AB be equation i and N₂+3H₂ ⇄2NH₃ be equation ii.

The two reactions differ in that ii is a thermo-chemical reaction whereas i is not. This is because energy is included in reaction ii but not included in reaction i.

Also i is a reaction of pure a element with a compound while ii is a reaction between two pure elements. The compound is BC while the pure element is A.

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Which piece of laboratory glassware did you find to be more efficient for the solvent extraction procedure, and why?

Anna [14]

Answer:

Condenser

Explanation:

Condenser is highly efficient when dealing with the vapors of the product are need to be liquified. It is mostly automated and regularly condenses the incoming vapors into liquid. It is very easy to use. All we have to do it to attach incoming and outgoing flow pipes and constantly monitor the flow of cold water through the condenser. It is made up of special kind of PYREX glass so that it won't break when dealing with steam.

7 0

4 years ago

At a pressure of 505 kPa, the volume of a gas is 12.00 mL. Assuming the temperature remains constant,

Sergio [31]

Answer:

757.5 kPa

Explanation:

Boyle's law states that p1 * v1 = p2 * v2

v1 = 12 mL

v2 = 8 mL

p1 = 505 kPA

p2 = ?

(505)(12) = (p2)(8)

6060 = (p2)(8)

p2 = 757.5

8 0

3 years ago

The half-life of radioactive substance is 2.5 minutes. what fraction of the origional radioactive remains after 10 mins

saul85 [17]

The answer is 1/16.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. $(1/2)^{n} = x$ ,
where:
n - a number of half-lives
x - a remained fraction of a sample

2. $t_{1/2} = \frac{t}{n}$
where:
 $t_{1/2}$ - half-life
t - total time elapsed
n - a number of half-lives

So, we know:
t = 10 min
 $t_{1/2}$ = 2.5 min

We need:
n = ?
x = ?

We could first use the second equation to calculate n:
If:
$t_{1/2} = \frac{t}{n}$ ,
Then:
$n = \frac{t}{ t_{1/2} }$
⇒ $n = \frac{10 min}{2.5 min}$
⇒ $n=4$ 

Now we can use the first equation to calculate the remained fraction of the sample.
 $(1/2)^{n} = x$
⇒ $x=(1/2)^4$
⇒ $x= \frac{1}{16}$