Not free enslaved not having free will
ALL of them
I just go a A+ on this hope this helps. :D
Answer:
your answer is letter A.working together to complete a project or a task
For calculating the average of cells C2 through C30 use the COMPUTE statement = AVERAGE(C2:C30).
Explanation:
- Excel a software program created by Microsoft that uses spreadsheets to organize numbers and data with formulas and functions.
- Excel analysis is ubiquitous around the world and used by businesses of all sizes to perform financial analysis.
- The AVERAGE function calculates the average of numbers provided as arguments.
- To calculate the average, Excel adds the numbers together and divides by the total number of values supplied. AVERAGE can handle up to 255 individual arguments, which can include numbers, cell references, ranges, arrays, and constants.
- To perform the average formula in Excel, enter the values, cells, or range of cells of which you're calculating the average in the format, =AVERAGE(number1, number2, etc.) or =AVERAGE(Start Value:End Value). This will calculate the average of all the values or range of cells included in the parentheses.
Answer:
# input the number of temperatures required, which will be 10 here, but the user can print any number.
n=input("Enter the number of temperatures you want")
# create a list which can have n temperatures since it starts from 0, the maximum is n-1, and n needs to be converted to an integer.
temp= [0,int(n)-1]
#declared a variable of float type. As its 0.0 it will be a float, if 0 then integers, and so on
s=0.0
#running a for loop n times, and hence 0 to n-1.
for i in range(0, int(n)):
temp[i]=input("Enter the temperature in degree celsius in float")
s=s + float(temp[i])
i=i+1
print("The sum of the temperatures is:{0:0.1f}", +s)
Explanation:
The question from edhesive is: You need to write a program that calls for ten temperatures and then find the sum of temperatures. The temperature should be in float, which is expected. And the program is as being mentioned in the answer section.