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iris [78.8K]
4 years ago
12

Determine whether the equation 2(h+1)=5h−7 has one solution, no solution, or infinitely many solutions. The equation has . Quest

ion 2 If the equation has a solution, enter it below. If the equation has no solution or infinitely many solutions, leave the solution field blank.

Mathematics
2 answers:
bagirrra123 [75]4 years ago
8 0
The answer to the question is one solution

attashe74 [19]4 years ago
5 0

Answer:

The equation 2(h+1)=5h−7 has one solution

and solution is: h=3

Step-by-step explanation:

We have to determine the number of solutions of the equation:

2(h+1)=5h−7

Now, on solving it

2h+2= 5h-7

Taking terms of h on one side and constant on other, we get

5h-2h= 7+2

i.e. 3h= 9

Dividing both sides by 9, we get

h= 3

Hence, the equation 2(h+1)=5h−7 has one solution

and solution is: h=3

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Solve for the value of each letter.
creativ13 [48]

Answer:

Step-by-step explanation:

1] 6x + 10 = 28  {subtract 10 from both sides}

6x + 10 -10 = 28 - 10

6x = 18  {Divide both sides by 6}

6x/6 = 18/6

x = 3

2]  -2m - 4 = 8 {Add 4 to both side}

 -2m - 4 + 4 = 8 + 4

-2m = 12  {Divide both sides by -2}

-2m/-2 = 12/-2

m = -6

3] x + x + 2x = 48  {add the like terms}

  4x = 48  {divide both sides by 4}

4x/4 = 48/4

x = 12

4] 3y +4 +3y  - 6 = 34 {add the like terms}

   6y - 2 = 34  {Add 2 to both side}

6y - 2 + 2 = 34 +2

6y = 36 {divide both sides by 6}

6y/6 = 36/6

y = 6

5]9(w - 6) = 36 {divide both sides by 9}

[9(w - 6)]/9 = 36/9

w - 6 = 4  {Add 6 to both sides}

w - 6 + 6 = 4 + 6

w = 10

4 0
3 years ago
Read 2 more answers
2. The cone has a radius of 30 mm and slant height of 34 mm. What is the height h for this cone?​
Flura [38]

Answer:

h = 16

Step-by-step explanation:

By applying the Pythagorean Theorem, the slant height is given by the formula:

\sqrt{r^2+h^2}

34 = \sqrt{30^2 + h^2}

34^2 = 30^2 + h^2

1156 = 900 + h^2

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h = \sqrt{256}

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6 0
3 years ago
Please help with parts (a), (b),and (c).No need much explanation
fomenos

Given the Histogram that summarizes the data obtained by Kemala:

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In order to find the Class Width, you need to subtract the lowest value of each bar from the lowest value of the previous bar.

In this case, you get:

\begin{gathered} 5-2=3 \\ 8-5=3 \\ 11-8=3 \end{gathered}

Therefore:

Class\text{ }Width=3

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Then, you get:

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(a)

3

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2 years ago
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Answer:

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