Given:
Point Q is on line segment PR.
QR = 3x, PQ = x + 6, and PR = 5x – 4.
To find:
The numerical length of PQ.
Solution:
Since, point Q is on line segment PR, so by segment addition property, we get
The value of x is 10.
Now,
Putting x=10, we get
Therefore, the numerical length of PQ is 16 units.
Answer:
3 7/9
Step-by-step explanation:
Answer:
∠ 2 = 45°
Step-by-step explanation:
∠ 1 and ∠ 2 are same- side interior angles and are supplementary, thus
∠ 2 = 180° - ∠ 1 = 180° - 135° = 45°
subtract the 2 to find the difference:
279.48 - 250.55 = 28.93
divide difference by actual amount:
28.93 / 279.48 = 0.1035
rounded to the nearest tenth = 10.4%
Answer:
a)
Step-by-step explanation:
for each point (A, B, C) reduce the 'x-value' by two and reduce the 'y-value' by 7
for example, for point A:
to find A': (-6, -7) would be (-6-2, -7-7) which is (-8, -14)
