Question

In ΔHIJ, the measure of ∠J=90°, JI = 5, IH = 13, and HJ = 12. What is the value of the sine of ∠H to the nearest hundredth?

Answer 1

Given:

Given that HIJ is a right triangle.

The measure of ∠J is 90°, JI = 5, IH = 13, and HJ = 12.

We need to determine the value of sine of ∠H

Value of sine ∠H:

The value of sine ∠H can be determined by using the trigonometric ratios.

Thus, we have;

$sin \ H=\frac{JI}{IH}$

Substituting the values, we get;

$sin \ H=\frac{5}{13}$

Dividing, we get;

$sin \ H=0.3846$

Taking $sin^{-1}$ on both sides, we have;

$H=sin^{-1}(0.3846)$

$H=22.6189$

Rounding off to the nearest hundredth, we get;

$H=22.62^{\circ}$

Thus, the measure of ∠H is 22.62°

Answer 2

Answer:

.38

Step-by-step explanation: